Question 1) The figure shows a person wearing weight boots and doing lower leg flexion/extension exercise in sitting position to strengthen the quadriceps muscles and a simple mechanical model of his leg. W 1 is the weight of the lower leg, Wo is the weight of the boot, FM is the magnitude of the pulling force exerted on the tibia by the quadriceps muscles through the patellar tendon, F, is the magnitude of the reaction force acting on the tibiofemoral joint. Point O is the center of the tibiofemoral joint, Point A is the point where the patellar tendon attaches to the tibia, Point B is the center of gravity of the lower leg, C point of gravity is the center of gravity of the boat. The distances between point O and points A, B and C were measured as a=10 cm, b=22 cm and c=43 cm, respectively. The angle between the long axis of the tibia and the horizontal is B=38°, the angle between the action line of the quadriceps muscle strength and the long axis of the tibia is a=18 ° . Points O, A, B and C lie along a straight line. The WO weight of the boot is 0.5 times the W1 weight of the lower leg of the person (W0 = 0.5 W 1). muscle strength FM Since it is given as = 460 N; F₁ Fj FM FM W₁ Wo a b A B W₁ BA Wo
Question 1) The figure shows a person wearing weight boots and doing lower leg flexion/extension exercise in sitting position to strengthen the quadriceps muscles and a simple mechanical model of his leg. W 1 is the weight of the lower leg, Wo is the weight of the boot, FM is the magnitude of the pulling force exerted on the tibia by the quadriceps muscles through the patellar tendon, F, is the magnitude of the reaction force acting on the tibiofemoral joint. Point O is the center of the tibiofemoral joint, Point A is the point where the patellar tendon attaches to the tibia, Point B is the center of gravity of the lower leg, C point of gravity is the center of gravity of the boat. The distances between point O and points A, B and C were measured as a=10 cm, b=22 cm and c=43 cm, respectively. The angle between the long axis of the tibia and the horizontal is B=38°, the angle between the action line of the quadriceps muscle strength and the long axis of the tibia is a=18 ° . Points O, A, B and C lie along a straight line. The WO weight of the boot is 0.5 times the W1 weight of the lower leg of the person (W0 = 0.5 W 1). muscle strength FM Since it is given as = 460 N; F₁ Fj FM FM W₁ Wo a b A B W₁ BA Wo
Related questions
Question
Question 1-A) Find the W1 weight of the lower leg .
Question 1-B) Find the component (F Jx ) of the joint reaction force in the x direction .
Question 1-C) Find the component (F Jy ) of the joint reaction force in the y direction .
Question 1-D) Find the resultant of the joint reaction force (F J )
Question 1-E) Find the angle γ (Gamma) of the joint reaction force with the horizontal
![Question 1) The figure shows a person wearing weight boots and doing lower leg flexion/extension exercise in sitting
position to strengthen the quadriceps muscles and a simple mechanical model of his leg. W 1 is the weight of the lower
leg, Wo is the weight of the boot, FM is the magnitude of the pulling force exerted on the tibia by the quadriceps
muscles through the patellar tendon, F, is the magnitude of the reaction force acting on the tibiofemoral joint. Point
O is the center of the tibiofemoral joint, Point A is the point where the patellar tendon attaches to the tibia, Point B is
the center of gravity of the lower leg, C point of gravity is the center of gravity of the boat. The distances between
point O and points A, B and C were measured as a= 10 cm, b=22 cm and c=43 cm, respectively. The angle
between the long axis of the tibia and the horizontal is B=38°, the angle between the action line of the quadriceps
muscle strength and the long axis of the tibia is a=18 ° . Points O, A, B and C lie along a straight line. The WO weight
of the boot is 0.5 times the W1 weight of the lower leg of the person (Wo= 0.5 W 1). muscle strength FM Since it
is given as = 460 N;
Fj
Fj FM
FM
B
W₁
Wo
n
C
B
W₁ B
Wo](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4561f935-69d8-4e57-b508-cecfbc0b2c2e%2F27ef09ad-ccad-4498-a865-56cdb009c7ef%2Fxixmwn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 1) The figure shows a person wearing weight boots and doing lower leg flexion/extension exercise in sitting
position to strengthen the quadriceps muscles and a simple mechanical model of his leg. W 1 is the weight of the lower
leg, Wo is the weight of the boot, FM is the magnitude of the pulling force exerted on the tibia by the quadriceps
muscles through the patellar tendon, F, is the magnitude of the reaction force acting on the tibiofemoral joint. Point
O is the center of the tibiofemoral joint, Point A is the point where the patellar tendon attaches to the tibia, Point B is
the center of gravity of the lower leg, C point of gravity is the center of gravity of the boat. The distances between
point O and points A, B and C were measured as a= 10 cm, b=22 cm and c=43 cm, respectively. The angle
between the long axis of the tibia and the horizontal is B=38°, the angle between the action line of the quadriceps
muscle strength and the long axis of the tibia is a=18 ° . Points O, A, B and C lie along a straight line. The WO weight
of the boot is 0.5 times the W1 weight of the lower leg of the person (Wo= 0.5 W 1). muscle strength FM Since it
is given as = 460 N;
Fj
Fj FM
FM
B
W₁
Wo
n
C
B
W₁ B
Wo
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