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QUESTION 1 Suppose an electron (q= -e= - 1.6 x 10-19 C.m=9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K = -U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=

QUESTION 1 Suppose an electron (q= -e= - 1.6 x 10-19 C.m=9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K = -U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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QUESTION 1 Suppose an electron (g = - e = -1.6 x 10-19 C,m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vah = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significont figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U =0 K=-U Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s
Transcribed Image Text:QUESTION 1 Suppose an electron (g = - e = -1.6 x 10-19 C,m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vah = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significont figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U =0 K=-U Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s
QUESTION 2 Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so: | = |1+ Using, Ohm's Law V = | we derive, that 1 = V1/ 12 = V2/ 13=V3/ Since, the voltage is the same on all resistors, then V = V1 = Substituting to the, first equation above, we get the following + V2/ + V3/ + | = V1/ So: 1 1 1 1 + R2 Rea Reg R1 R3
Transcribed Image Text:QUESTION 2 Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so: | = |1+ Using, Ohm's Law V = | we derive, that 1 = V1/ 12 = V2/ 13=V3/ Since, the voltage is the same on all resistors, then V = V1 = Substituting to the, first equation above, we get the following + V2/ + V3/ + | = V1/ So: 1 1 1 1 + R2 Rea Reg R1 R3
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