QUESTION 1 Suppose an electron (q= -e= - 1.6 x 10-19 C.m=9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U= Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K = -U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s v=

University Physics Volume 2
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Chapter10: Direct-current Circuits
Section: Chapter Questions
Problem 68AP: A circuit contains a D-cell battery, a switch, a 20- resistor, and three 20-mF capacitors. The...
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QUESTION 1
Suppose an electron (g = - e = -1.6 x 10-19 C,m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vah = +5000 V. Solve for the final
speed of the electron. Express numerical answer in two significont figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U =0
K=-U
Since K=
mv and using the formula for potential energy above, we arrive at an equation for speed:
2
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
Transcribed Image Text:QUESTION 1 Suppose an electron (g = - e = -1.6 x 10-19 C,m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vah = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significont figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U =0 K=-U Since K= mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s
QUESTION 2
Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel.
Sol.
In a parallel connection, voltage drops across the resistors so:
| = |1+
Using, Ohm's Law
V = |
we derive, that
1 = V1/
12 = V2/
13=V3/
Since, the voltage is the same on all resistors, then
V = V1 =
Substituting to the, first equation above, we get the following
+ V2/
+ V3/
+
| = V1/
So:
1
1
1
1
+
R2
Rea
Reg
R1
R3
Transcribed Image Text:QUESTION 2 Find the expression for the equivalent resistance of 3 resistors (R1,R2,R3) connected in parallel. Sol. In a parallel connection, voltage drops across the resistors so: | = |1+ Using, Ohm's Law V = | we derive, that 1 = V1/ 12 = V2/ 13=V3/ Since, the voltage is the same on all resistors, then V = V1 = Substituting to the, first equation above, we get the following + V2/ + V3/ + | = V1/ So: 1 1 1 1 + R2 Rea Reg R1 R3
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