Question 1 ♥ Part (a) I measure the resistance of this wire and find it to be R = 156 Q2. What is the resistivity of the material the wire is made out of? p=5.182 *10-4 p=5.182 x 10-4 ✓ Correct! Part (b) What is the conductivity of this wire, in inverse Ohms per meter? 1930. ✔Correct! o=1929.8 Part (c) Calculate the current in the wire, in milliamperes, if the field strength is 5.28 V/m. 1= Question 2 A particular wire has a length of L=2.7 m and a circular cross-sectional area of radius r= 1.69 mm. Correct Answer E-Pat sin() cotan() atan() cosh()) cos() tan() asin()) acos() acotan() sinh() tanh() cotanh() Degrees O Radians E-4.752 x 10 ✓ Correct! You leave a 110 W light bulb on for 12 hours in the day. Part (a) Express energy through power and time interval dr. Student Final Submission E-Pat Part (b) How much energy has been used in joules? cos() tan() sin() cotan() asin() acos() atan() acotan() sinh() cosh() tanh() cotanh() π(7 EM 1 + END NO BACKSPACE DEL CLEAR Degrees O Radians Feedback Correct! * Part (c) If the energy used were used to lift a weight of m=225 kg, write an equation of the height that the weight can be lifted in terms of P, 4t, and m -(P) (Mt)(mg) ✔Correct! Part (d) Calculate the numerical value of h. h=|| 8 9 4 5 6 12 3 0 A (78 9 HOME EM4 5 6 1 2 3 0 NO BACKSPACE END CLEAR HOME

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Temperature Variance of Resistance

Electrical resistance or simply resistance is the property of a material that opposes the free flow of electrons through it. The total amount of resistance to the flow of charges (or current) is affected by many factors like the length of the conducting material, its cross-sectional area, resistivity, and temperature.