QUESTION 1 In the circuit shown, determine the following: a.) The terminal voltage of battery E6 is b (a) 22 (b) 21 (c.) 17 (d ) 18 (e) 19 b.) The potential difference, Vge is c V. (a) – 22 (b) 22 (c) - 2 (d) 2 (e) 12 c.) The terminal voltage of battery , ES is d (a) 8 (b) 7 (c) 6 (d) 18 (e) 12 d.) The potential difference, Vce is b V. (a) 16 (b) 12 (c) 10 (d) 8 (e) 18 e.) The potential difference, Vdg is e V. (a) 8 (b) – 12 (c) -8 (d) - 10 (e) 10 b 20 C 20 El- 6v, 0.52 E2= 11v, 0.52 E3= 7v, 0.52 E6- 20v, 0.50 ES= 7v, 0.50 E4= 19v, 0.50 f 20 e 20

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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QUESTION 1
In the circuit shown, determine the following:
a.) The terminal voltage of battery E6 is b
(a) 22
(b) 21
(c.) 17
(d) 18
(e) 19
b.) The potential difference, Vge is c
V.
(a) – 22
(b) 22
(c) - 2
(d) 2
(e) 12
c.) The terminal voltage of battery, E5 is d
V
(a) 8
(b) 7
(c) 6
(d) 18
(e) 12
d.) The potential difference, Vce is b
V.
(a) 16
(b) 12
(c) 10
(d) 8
(e) 18
e.) The potential difference, Vdg is e
V.
(a) 8
(b) – 12
(c) - 8
(d) - 10
(e) 10
a
b
C 20
E1= 6v, 0.50
E2= 11v, 0.50
E3= 7v, 0.52
= E6= 20v, 0.52
E5= 7v, 0.50
E4= 19v, 0.50
f 20
Transcribed Image Text:QUESTION 1 In the circuit shown, determine the following: a.) The terminal voltage of battery E6 is b (a) 22 (b) 21 (c.) 17 (d) 18 (e) 19 b.) The potential difference, Vge is c V. (a) – 22 (b) 22 (c) - 2 (d) 2 (e) 12 c.) The terminal voltage of battery, E5 is d V (a) 8 (b) 7 (c) 6 (d) 18 (e) 12 d.) The potential difference, Vce is b V. (a) 16 (b) 12 (c) 10 (d) 8 (e) 18 e.) The potential difference, Vdg is e V. (a) 8 (b) – 12 (c) - 8 (d) - 10 (e) 10 a b C 20 E1= 6v, 0.50 E2= 11v, 0.50 E3= 7v, 0.52 = E6= 20v, 0.52 E5= 7v, 0.50 E4= 19v, 0.50 f 20
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