QUESTION 1 In a burger shop, a sample of 67 days, was taken to study the daily sales, It was found that the mean daily sales are (m) with a standard deviation is (d). The confidence interval for the population mean is computed, the upper confidence limit is 31, and the lower confidence limit is 11 Calculate the value of m? (Round answer to two decimal places ex. 2.09)

Q: suppose that 50 students were randomly sampled and their mean age was 30.4 years old. the population…

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Q: FIND A 90% CONFIDENCE INTERVAL FOR THE DIFFERENCE IN POPULUTION PROPORTIONS Pf -Pm  round your…

A: Given:  n1=100, n2=50, p1^=0.24, p2^=0.43 We find the 90% C.I. for the difference in population…

Q: help me

A: The objective of this question is to calculate the 95% confidence interval for the mean serum…

Q: A group of 10 students from elementary school has their height measured. The sample mean is 119 cm…

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Q: Do men take more time than women to get out of bed in the morning? The 47 men observed averaged 5.4…

A: 1. In this case, two independent groups of individuals- men and women are being compared, based on…

Q: In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were Next question…

A: Given : Sample Size, n = 50 Sample Mean, x̄ = 5.7 sample standard…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: It is given that the sample mean is 32 and the population standard deviation is 4.1.

Q: The 95% confidence interval for the population slope was calculated as (0.751,0.947). Based on the…

A: We have given  The confidence interval for slope is given to be (0.751, 0.947)

Q: A sample of 26 observations is taken from a normal distribution with unknown mean, the sample mean…

A: Answer: From the given data, Sample size(n) = 26 mean (x¯) = 12.6 Standard deviation(σ) = 2.5 95%…

Q: For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight…

A: Given,sample size(n)=55sample mean(x)=32standard deviation(σ)=4.1α=1-0.90=0.1α2=0.05z0.05 =1.645

Q: A study was done of 6 patients admitted to a hospital.   Their ages (x) and systolic blood pressure…

A: Given: n = 6 Formula Used: Confidence Interval = b ± t* ·Se Slope b = n∑XY-∑X∑Yn∑X2-∑X2 Standard…

Q: 90% confidence

A: Given that  90% Confidence interval for mean = ( 75.3 to 80.9 ) Null hypothesis (Ho) : μ=70…

Q: We want to compare cholesterol levels between men and women, so we collect a sample of 20 women and…

A: From the given information,

Q: A group of 65 randomly selected students have a mean score of 30.6 with a standard deviation of 5.4…

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Q: An IQ test is designed so that the mean is 100 and the standard deviation is 17 for the population…

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Q: How much more sensitive to contrast are athletes with eye grease than without eye grease? Give a 95%…

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Q: Question 37 SAT scores are distributed with a mean of 1,500 and a standard deviation of 300. You…

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Q: Overweight Men For a random sample of 70 overweight men, the mean of the number of pounds that they…

A: The sample size is 70, the sample mean is 29 and the population standard deviation is 4.3.

Q: The distribution of study times for first-year students follows a normal distribution with a…

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Q: The 90% confidence interval for the true mean of national statistics examination scores is 81 < ? <…

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Q: In an exam for a statistics class, the class average is 68 with a standard deviation 4. If a student…

A: Given mean μ= 68, standard deviation σ= 4 Let X: score of the students = 75

Q: The scores on a standardized test are normally distributed with a mean of 90 and standard deviation…

A: The test score is 0.6 standard deviations above the mean is obtained below: From the given…

Q: A random sample of 125 adult females was selected as part of a study on weight loss. The average…

A: Given: n=125, x=212 pounds, σ=18, α=1-0.95=0.05

Q: the sample proportion of females is  x=118  n=164 P = .720  #1 Make a 95% confidence interval for…

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Q: The mean age from a sample of 42 employees at Stats R Us is 22, with a standard deviation of 5.73.…

A: given that,sample mean, x =22standard deviation, s =5.73sample size, n =42

Q: Bob samples 30 one-pound bags of celery hearts from the produce section at Kroger's. He weighs each…

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Q: A sample of 22 adults attending a country fair determined that the mean age was 35 given that the…

A: Answer: From the given data, Sample size(n) = 22 mean (x¯) = 35 Standard deviation(σ) = 10 95%…

Q: For a random sample of  70  overweight men, the mean of the number of pounds that they were…

A: Here, n = 70, CL = 0.99, x=28, and σ=3.8

Q: The mean score of Grade 11 students in a General Math examination was observed to be 75 with a…

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Q: The sample correlation is -0.8. If the sample size was 40, then the 99% confidence interval states…

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Q: Noise levels at various area urban hospitals were measured in decibels. The mean of the noise levels…

A: We have given that Sample size (n) = 81Sample mean (x̅) = 62.04Population Standard deviations (σ) =…

Q: A teacher gives a test to his class of 25 students. Since he wants to quickly obtain an estimate of…

A: The class of 25 students is considered as the population. Sample size n =12 Sample mean x¯=82 Sample…

Q: A survey taken several years ago found that the average time a person reading a newspaper was…

A: Given:

Q: What should the minimum IQ score be so that 90% of all students in the area can qualify for…

A: The value of z at the lowest 90%, i.e., corresponding to the left to the 90% area (p=0.90) of the…

Q: A sample of 28 adults attending a country fair determined that the mean age was 33,given that the…

A:

Q: The mean number of English courses taken in a two-year time period by male and female college…

A: a)The null hypothesis isH0:μM=μF

Q: In a survey conducted to 415 people it was found that they had walked 5000 meters on average for the…

A: Sample size (n) = 415Sample mean (x̅) = 5000Standard deviations (s) = 900 Confidence level (c) =…

Q: A camp director is interested in the mean number of letters each child sends during his or her camp…

A: From the given information we find the solution.

Q: The mean change in muscle thickness observed after a 4-week training regimen was 4 mm, and the 95%…

A: The 95% confidence interval is (-0.5, 8.5).

Q: Aassume that adults have iq scores that are normally distributed with a mean of 96.1 and a standard…

A: Mean(µ) = 96.1Standard deviations (σ) = 18.2 X ~ N (µ, σ )= N(96.1,18.2)