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- Standard error stream outputs are directed to the stream objects_____________________What are the assumptions that can be made from the program below #include<stdio.h>#include<stdlib.h>#include<string.h> //structuretypedef struct{char Username[20];int cents;}value; int *coinChange(int change); //main functionint main(){ FILE *f; //open the filef = fopen("coins.txt", "r"); //check if file not openedif(f==NULL){printf("File not opened!");return 1;} value arr[10];int i, j, n, option, totalCoins;char name[20];int *coins; // = //read the filefor(i=0; !feof(f) ; i++){fscanf(f, "%s", arr[i].Username);fscanf(f, "%d", &arr[i].cents);} n = i; //close the filefclose(f); //loopwhile(1){//display menuprintf("1. Enter name\n");printf("2. Exit\n\n"); //prompt and read optionprintf("Enter option (1 or 2): ");scanf("%d", &option); //switch statementswitch(option){case 1://read the namescanf("%s", name);totalCoins = 0;//search in the listfor(i=0; i<n; i++){if(!strcmp(name, arr[i].Username)){totalCoins = totalCoins + arr[i].cents;}}//check if not…Write an assembly language program that requests input from the keyboard for two positive integers greater than 0 then it calculates and displays the greatest common divisor (GCD). The greatest common divisor (GCD) of two integers (numbers), is the largest number that divides them both without a reminder. For example, 21 is the GCD of 252 and 105 (because 252 = 21 × 12 and 105 = 21 × 5). Since 21 is the greatest common number that divides both integers it is the GCD. Your program must define and use the following procedures: Procedure Main: This is the main procedure of the program which makes the correct sequence of calls to other procedures and displays the program title as shown in the sample run. Procedure Read_Numbers: This procedure prompts for input and reads the value of two positive integers. This procedure makes use of the procedure Check_Value (defined below) which checks if a value is out of range and displays the error message. If the returned value in BL is 0 (error) then…
- Find output of below program int main(){int c1,c2;int a = -8;int b = 3;c1 = --a + b;c2 = a-- + b;cout<<"c1="<<c1<<", "<<"c2="<<c2<<endl; return 0;} (A) c1=-7,c2=-4(B) c1=-7,c2=-3(C) c1=-4,c1=b-3(D) c1=-6,c2=-6Cite an error in this script #include using namespace std; int main() B{ int a="99"; float b='2.8'; string g-Eng; char m=g; cout<Why can't I run the code?1. Write a function num_double to read file (f1.txt), double all the numbers, keep the string (no change), and write to another file (f2.txt), for example: >>># f1.txt-“I have 5 books and 3 pens...” >>> f2 = num_double(f1) >>> # f2.txt – “I have 10 books and 6 pens ...”How this program would be improved? #include<string.h> #include<stdio.h> #include <fstream> #include<ctype.h> #include<conio.h> #include<iostream> #include<stdlib.h> using namespace std; class Nodo { char Nombre[128]; Nodo * siguiente; public: Nodo(char *N='\0',Nodo * S=NULL) { strcpy(Nombre, N); siguiente=S; } friendclass Lista; }; class Lista { Nodo * inicio; public: Lista() { inicio=NULL; } void Insertar(char*); void Guardar(); void Recuperar(); void Recorrer(); }; void Lista::Insertar(char * N) { Nodo *nuevo=inicio; nuevo=new Nodo(N,inicio); inicio=nuevo; } void Lista::Guardar() { Nodo *aux=inicio; char Nombre_archivo[128]; cout<<endl<<"nombre del archivo a guardar: "; gets(Nombre_archivo); ofstream archivo_salida(Nombre_archivo); if(archivo_salida.fail()){ cout << "Error al abrir el archivo..." << endl; system("pause"); return; } while(aux) { archivo_salida<<aux->Nombre<<endl;…C++ Please Help!What would be printed from the following lines of code? cout << fixed << setprecision (2) << 124.78560 << endl; cout << fixed << setprecision (2) << 0.14 << endl; cout << fixed << setprecision (2) << 20 << endl; cout << fixed << setprecision (2) << 14767.0 << endl; cout << fixed << setprecision (4) << 124.79 << endl; cout << fixed << setprecision (4) << 0.14 << endl; cout << fixed << setprecision (4) << 20.0 << endl; cout << fixed << setprecision (4) << 14767.00 << endl;Study the following code segment and identify the line that will cause a syntax error void Secret (ints x 8, double y- 12.34, char z-w : e int main() /Line 2 ILine 3 1/Line 4 23: double b 48.78: char ch - M Secret (a, return 0: int a b, ch): void Secret (ints x, double y, char z) Fine x 2 x; cout << x ", "<3:49 A docs.google.com اجب ب صح او خطا ;cin>w>>f ;cin>c;couut>b>>cout<SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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