Question 1 a) In J. J. Thomson experiment (1897), an electron moving horizontally with a constant speed vo enters in between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d, is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge to mass ratio, i.e. e/m to be 2v,Y/CEL). (Recall that Thomson received Nobel Prize for his achievement.) b) Calculate e/m, knowing the following data. E=1.6x10* Newton/Coulomb, L=10 cm, Y=2.9 cm, v=2.19x10* km/s. (Be careful to use coherent units.)

Question 1 a) In J. J. Thomson experiment (1897), an electron moving horizontally with a constant speed vo enters in between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d, is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge to mass ratio, i.e. e/m to be 2v,Y/CEL). (Recall that Thomson received Nobel Prize for his achievement.) b) Calculate e/m, knowing the following data. E=1.6x10* Newton/Coulomb, L=10 cm, Y=2.9 cm, v=2.19x10* km/s. (Be careful to use coherent units.)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

An electron is to be accelerated in a uniform electric field having a strength of 1.90 106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.810 m?_________ keV(b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV (as in the Stanford Linear Accelerator, which is actually smaller than this)? ________km
An electron is to be accelerated over a distance 3.84m in a uniform electric field having a strength of 6.04x 10 V m What distance is required to give the electron a kinetic energy of 6.74GeV (in m)? M 31
Two horizontal parallel plates are separated by a distance of 165mm creating an electric field of 32 µN/C directed north. An electron is place halfway between the two plates with and fired with initial velocity 67m/s from the horizontal. Calculate the time it takes for the electron to land at the positive plate and its speed before hitting the plate,
An evacuated tube uses an accelerating voltage of 55 kV to accelerate electrons to hit a copper plate and produce X-rays. Non-relativistically, what would be the maximum speed (in m/s) of these electrons?
A uniform, 2.00 × 106 -V/m electric field is used to accelerate an electron. (a) Calculate the energy the electron acquires once it has moved 40.0 cm across this field. (b) Find the distance it must move across the field to increase its energy by 50.0 GeV.
If a proton and electron are released when they are 2.0 m apart, find the initial acceleration of electron (in m/s2) The answer (in fundamental SI unit) is
Please Help ASAP!!!!
An electron traveling in the +x direction with a speed of 3.2x10^5 m/s is electrically in the same direction as the direction of motion it entersstopped within 2 ns in the field. What will be the magnitude of the electric field in V/m? (e=1.6x10^-19 C,m=9.1x10^-31 kg) A) 980 B) 910 C) 840 D) 1120 E) 1050
In this experiment oil drops are suspended in a vertical electric field against the gravitational force to measure their charge. If the mass of a negatively charged drop suspended in an electric field of 1.76 ✕ 10−4 N/C strength is 2.299 ✕ 10−20 g, find the number of excess electrons in the drop.
An electron (-q = -1.602 x 10-19C) moves along a straight line from point a to point b with a separation distance d = 0.65m. Considering the electric field along this line is uniform with magnitude of 1.75x10^7 V/m and directed from point a to point b. What is the force on the electron? A) 2.4x10^-12 N B) -2.4x10^-12 N C) 2.8035x10^-12 N D) -2.8035x10^-12 N
A parallel-plate capacitor has a plate separation d=20 mm. A potential difference V=1129 volts exists between the plates. What is the magnitude of the force (in Newton) on a proton between the plates?. The charge of proton e=1.6*1019 C.
E7P9