Question 01. Using the Fadum chart provided, calculate the total vertical stress due to 200 kPa uniform contact pressure at a depth of 6m below point A for the rectangular raft foundation as per Question 1 part of the attached image. L1 = 7m L2 = 3m B1 = 9m B2 = 4m

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Question 01.

Using the Fadum chart provided, calculate the total vertical stress due to 200 kPa uniform contact pressure at a depth of 6m below point A for the rectangular raft foundation as per Question 1 part of the attached image.

L1 = 7m

L2 = 3m

B1 = 9m

B2 = 4m

 

Question 02.

A section of the proposed foundation in Question 01 has an obstruction. A redesign is carried out as shown in Question 2 part of the attached image. The original proposed footprint was maintained, and the section removed from the design has a width of B3 = 2m
Calculate the total vertical stress at the same depth below A and the same uniform pressure in Question 01.

B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁
Transcribed Image Text:B₁ B₁ Question 01 Question 02 4₁ L₁ A. A L₂ 4₂ ITE B₂ B₁ 2 B₁
Z
Influence value, /
0.16
0.01
0.14
0.12
0.10
0.08
0.06
0.04
0.02
Z
0
Oz
X
0.01
Load q, per unit of area
m 1 = 4;n=1/2
y
X
m = 0.0
m and n are interchangeable
σ₂ = qol
0.02 0.04
m=0.5,
Z
0.02
-X
m = ∞
0.04
0.1
m = 1.0
m = 2.0
0.1
0.2 0.3
∞ = E
0.2 0.3
0.28
0.26
0.6
0.24
0.22
0.20
0.18
0.5
0.5
Value of n
1
m = 0.5
m = 1.8
0.8 1
2
m = 2.0
2
3 4 6 8 10
m = 2.5
3
m=1.2
m=1.0
m=0.9
m=0.8
m = 0.7
m=0.6
m = 0.5
m = 0.4
m=0.3
m = 0.2
m = 0.1
m = 0.0
4
6
0.28
0.26
0.24
←
0.22
0.20
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
ㅎㅎ
0
8 10
m = ∞0
m = 3.0
m = 1.6
m = 1.4
Transcribed Image Text:Z Influence value, / 0.16 0.01 0.14 0.12 0.10 0.08 0.06 0.04 0.02 Z 0 Oz X 0.01 Load q, per unit of area m 1 = 4;n=1/2 y X m = 0.0 m and n are interchangeable σ₂ = qol 0.02 0.04 m=0.5, Z 0.02 -X m = ∞ 0.04 0.1 m = 1.0 m = 2.0 0.1 0.2 0.3 ∞ = E 0.2 0.3 0.28 0.26 0.6 0.24 0.22 0.20 0.18 0.5 0.5 Value of n 1 m = 0.5 m = 1.8 0.8 1 2 m = 2.0 2 3 4 6 8 10 m = 2.5 3 m=1.2 m=1.0 m=0.9 m=0.8 m = 0.7 m=0.6 m = 0.5 m = 0.4 m=0.3 m = 0.2 m = 0.1 m = 0.0 4 6 0.28 0.26 0.24 ← 0.22 0.20 0.18 0.16 0.14 0.12 0.10 0.08 0.06 0.04 0.02 ㅎㅎ 0 8 10 m = ∞0 m = 3.0 m = 1.6 m = 1.4
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Follow-up Question
B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁
Transcribed Image Text:B₁ B₁ Question 01 Question 02 4₁ L₁ A. A L₂ 4₂ ITE B₂ B₁ 2 B₁
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