Question 01. Using the Fadum chart provided, calculate the total vertical stress due to 200 kPa uniform contact pressure at a depth of 6m below point A for the rectangular raft foundation as per Question 1 part of the attached image. L1 = 7m L2 = 3m B1 = 9m B2 = 4m
Question 01. Using the Fadum chart provided, calculate the total vertical stress due to 200 kPa uniform contact pressure at a depth of 6m below point A for the rectangular raft foundation as per Question 1 part of the attached image. L1 = 7m L2 = 3m B1 = 9m B2 = 4m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Question 01.
Using the Fadum chart provided, calculate the total vertical stress due to 200 kPa uniform contact pressure at a depth of 6m below point A for the rectangular raft foundation as per Question 1 part of the attached image.
L1 = 7m
L2 = 3m
B1 = 9m
B2 = 4m
Question 02.
A section of the proposed foundation in Question 01 has an obstruction. A redesign is carried out as shown in Question 2 part of the attached image. The original proposed footprint was maintained, and the section removed from the design has a width of B3 = 2m
Calculate the total vertical stress at the same depth below A and the same uniform pressure in Question 01.
![B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba8b0b6a-ca21-4fd4-a561-cb3900d815a0%2F8d8063ad-d7bc-4c5a-8f9e-8c81979655e0%2Fewyjng_processed.jpeg&w=3840&q=75)
Transcribed Image Text:B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁
![Z
Influence value, /
0.16
0.01
0.14
0.12
0.10
0.08
0.06
0.04
0.02
Z
0
Oz
X
0.01
Load q, per unit of area
m 1 = 4;n=1/2
y
X
m = 0.0
m and n are interchangeable
σ₂ = qol
0.02 0.04
m=0.5,
Z
0.02
-X
m = ∞
0.04
0.1
m = 1.0
m = 2.0
0.1
0.2 0.3
∞ = E
0.2 0.3
0.28
0.26
0.6
0.24
0.22
0.20
0.18
0.5
0.5
Value of n
1
m = 0.5
m = 1.8
0.8 1
2
m = 2.0
2
3 4 6 8 10
m = 2.5
3
m=1.2
m=1.0
m=0.9
m=0.8
m = 0.7
m=0.6
m = 0.5
m = 0.4
m=0.3
m = 0.2
m = 0.1
m = 0.0
4
6
0.28
0.26
0.24
←
0.22
0.20
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
ㅎㅎ
0
8 10
m = ∞0
m = 3.0
m = 1.6
m = 1.4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fba8b0b6a-ca21-4fd4-a561-cb3900d815a0%2F8d8063ad-d7bc-4c5a-8f9e-8c81979655e0%2Fo8hmqqi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Z
Influence value, /
0.16
0.01
0.14
0.12
0.10
0.08
0.06
0.04
0.02
Z
0
Oz
X
0.01
Load q, per unit of area
m 1 = 4;n=1/2
y
X
m = 0.0
m and n are interchangeable
σ₂ = qol
0.02 0.04
m=0.5,
Z
0.02
-X
m = ∞
0.04
0.1
m = 1.0
m = 2.0
0.1
0.2 0.3
∞ = E
0.2 0.3
0.28
0.26
0.6
0.24
0.22
0.20
0.18
0.5
0.5
Value of n
1
m = 0.5
m = 1.8
0.8 1
2
m = 2.0
2
3 4 6 8 10
m = 2.5
3
m=1.2
m=1.0
m=0.9
m=0.8
m = 0.7
m=0.6
m = 0.5
m = 0.4
m=0.3
m = 0.2
m = 0.1
m = 0.0
4
6
0.28
0.26
0.24
←
0.22
0.20
0.18
0.16
0.14
0.12
0.10
0.08
0.06
0.04
0.02
ㅎㅎ
0
8 10
m = ∞0
m = 3.0
m = 1.6
m = 1.4
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![B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁](https://content.bartleby.com/qna-images/question/ba8b0b6a-ca21-4fd4-a561-cb3900d815a0/6035b780-8061-4551-b618-021f1c4a4875/yl7o43a_thumbnail.jpeg)
Transcribed Image Text:B₁
B₁
Question 01
Question 02
4₁
L₁
A.
A
L₂
4₂
ITE
B₂
B₁
2
B₁
Solution
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