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quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of X(f) as |f gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2-t) I-2,2] (t). (b) x₂(t) = \t\1₁-2.21 (t). w

quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of X(f) as |f gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2-t) I-2,2] (t). (b) x₂(t) = \t\1₁-2.21 (t). w

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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please have a graph for each in the time domain and frequency domain and show where the rate of decay would be with those graphs. also please have a detailed explanation and step by step process

Time-limited signals cannot be bandlimited, but their rate of decay in the fre- quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of X(f)| as |ƒ| gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2 t) I-2,2] (t). (b) x2(t) = tI-2,2] (t). (c) x3 (t) = cos(nt/4) I[-2,2] (t). - 1+1) 715-2210
Transcribed Image Text:Time-limited signals cannot be bandlimited, but their rate of decay in the fre- quency domain depends on the sharpness of the transitions in the time domain. For each of the time-limited signals below, estimate the rate of decay of X(f)| as |ƒ| gets large. You should be able to answer this without detailed computation of the Fourier transform. (a) x₁(t) = (2 t) I-2,2] (t). (b) x2(t) = tI-2,2] (t). (c) x3 (t) = cos(nt/4) I[-2,2] (t). - 1+1) 715-2210
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