Que A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water? 140 20 ft The area A of the sector is square feet. (Type an integer or decimal rounded to two decimal places as needed.)

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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### Sprinkler Coverage Area Calculation

A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water?

Here is a diagram illustrating the sprinkler's coverage area:
(The diagram shows a sector with a central angle of 140° and a radius of 20 feet.)

#### Question
The area \(A\) of the sector is \(\_\_\_\_\_\_\) square feet.
(Type an integer or decimal rounded to two decimal places as needed.)

---

### Calculation and Explanation
To find the area of the sector formed by the sprinkler, we use the formula for the area of a sector:

\[ A = \frac{\theta}{360} \times \pi r^2 \]

Where:
- \(\theta\) is the central angle (in degrees)
- \(r\) is the radius of the sector (distance the water is sprayed)

Given:
- \(\theta = 140°\)
- \(r = 20\) feet

Substituting the values:

\[ A = \frac{140}{360} \times \pi \times 20^2 \]

Now, calculate the area:

\[ A = \frac{140}{360} \times \pi \times 400 \]
\[ A = \frac{7}{18} \times \pi \times 400 \]
\[ A = \frac{7 \times 400}{18} \times \pi \]
\[ A = \frac{2800}{18} \times \pi \]
\[ A \approx 155.56 \pi \]
\[ A \approx 488.69 \text{ square feet} \]

Therefore, the area of the sector is approximately 488.69 square feet.

---

Please enter your answer in the answer box.
Transcribed Image Text:### Sprinkler Coverage Area Calculation A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water? Here is a diagram illustrating the sprinkler's coverage area: (The diagram shows a sector with a central angle of 140° and a radius of 20 feet.) #### Question The area \(A\) of the sector is \(\_\_\_\_\_\_\) square feet. (Type an integer or decimal rounded to two decimal places as needed.) --- ### Calculation and Explanation To find the area of the sector formed by the sprinkler, we use the formula for the area of a sector: \[ A = \frac{\theta}{360} \times \pi r^2 \] Where: - \(\theta\) is the central angle (in degrees) - \(r\) is the radius of the sector (distance the water is sprayed) Given: - \(\theta = 140°\) - \(r = 20\) feet Substituting the values: \[ A = \frac{140}{360} \times \pi \times 20^2 \] Now, calculate the area: \[ A = \frac{140}{360} \times \pi \times 400 \] \[ A = \frac{7}{18} \times \pi \times 400 \] \[ A = \frac{7 \times 400}{18} \times \pi \] \[ A = \frac{2800}{18} \times \pi \] \[ A \approx 155.56 \pi \] \[ A \approx 488.69 \text{ square feet} \] Therefore, the area of the sector is approximately 488.69 square feet. --- Please enter your answer in the answer box.
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