Que A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water? 140 20 ft The area A of the sector is square feet. (Type an integer or decimal rounded to two decimal places as needed.)
Que A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water? 140 20 ft The area A of the sector is square feet. (Type an integer or decimal rounded to two decimal places as needed.)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
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![### Sprinkler Coverage Area Calculation
A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water?
Here is a diagram illustrating the sprinkler's coverage area:
(The diagram shows a sector with a central angle of 140° and a radius of 20 feet.)
#### Question
The area \(A\) of the sector is \(\_\_\_\_\_\_\) square feet.
(Type an integer or decimal rounded to two decimal places as needed.)
---
### Calculation and Explanation
To find the area of the sector formed by the sprinkler, we use the formula for the area of a sector:
\[ A = \frac{\theta}{360} \times \pi r^2 \]
Where:
- \(\theta\) is the central angle (in degrees)
- \(r\) is the radius of the sector (distance the water is sprayed)
Given:
- \(\theta = 140°\)
- \(r = 20\) feet
Substituting the values:
\[ A = \frac{140}{360} \times \pi \times 20^2 \]
Now, calculate the area:
\[ A = \frac{140}{360} \times \pi \times 400 \]
\[ A = \frac{7}{18} \times \pi \times 400 \]
\[ A = \frac{7 \times 400}{18} \times \pi \]
\[ A = \frac{2800}{18} \times \pi \]
\[ A \approx 155.56 \pi \]
\[ A \approx 488.69 \text{ square feet} \]
Therefore, the area of the sector is approximately 488.69 square feet.
---
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Transcribed Image Text:### Sprinkler Coverage Area Calculation
A water sprinkler sprays water over a distance of 20 feet while rotating through an angle of 140°. What area of lawn receives water?
Here is a diagram illustrating the sprinkler's coverage area:
(The diagram shows a sector with a central angle of 140° and a radius of 20 feet.)
#### Question
The area \(A\) of the sector is \(\_\_\_\_\_\_\) square feet.
(Type an integer or decimal rounded to two decimal places as needed.)
---
### Calculation and Explanation
To find the area of the sector formed by the sprinkler, we use the formula for the area of a sector:
\[ A = \frac{\theta}{360} \times \pi r^2 \]
Where:
- \(\theta\) is the central angle (in degrees)
- \(r\) is the radius of the sector (distance the water is sprayed)
Given:
- \(\theta = 140°\)
- \(r = 20\) feet
Substituting the values:
\[ A = \frac{140}{360} \times \pi \times 20^2 \]
Now, calculate the area:
\[ A = \frac{140}{360} \times \pi \times 400 \]
\[ A = \frac{7}{18} \times \pi \times 400 \]
\[ A = \frac{7 \times 400}{18} \times \pi \]
\[ A = \frac{2800}{18} \times \pi \]
\[ A \approx 155.56 \pi \]
\[ A \approx 488.69 \text{ square feet} \]
Therefore, the area of the sector is approximately 488.69 square feet.
---
Please enter your answer in the answer box.
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