Quadratic Interpolation • a strategy for improving the estimate by introducing some curvature into the line connecting the points. If three data points are available, this can be accomplished with a second-order polynomial. X f(x) - f₂(x) = bo + b₁(x − xo) + b₂(x − xo) (x -x₁) 0 0 100 400 600 800 1000 200 0.82436 1 0.73576 0.40601 0.19915 0.09158 Find the value of the function at x = 482 using Quadratic Interpolation
Quadratic Interpolation • a strategy for improving the estimate by introducing some curvature into the line connecting the points. If three data points are available, this can be accomplished with a second-order polynomial. X f(x) - f₂(x) = bo + b₁(x − xo) + b₂(x − xo) (x -x₁) 0 0 100 400 600 800 1000 200 0.82436 1 0.73576 0.40601 0.19915 0.09158 Find the value of the function at x = 482 using Quadratic Interpolation
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Solve the following problem using the FORMULA given. READ INSTRUCTION DO NOT USE DIFFERENT FORMULA.
![Quadratic Interpolation
• a strategy for improving the estimate by introducing some
curvature into the line connecting the points. If three data
points are available, this can be accomplished with a
second-order polynomial.
f₂(x) = bo + b₁(x − xo) + b₂(x -xo) (x -x₁)
X
f(x)
0
0
100
400
600
800
1000
200
0.82436 1 0.73576 0.40601 0.19915 0.09158
Find the value of the function at x = 482 using
Quadratic Interpolation](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63a6f24c-64be-4d76-ad61-11d2bd9babb2%2F12567b9d-71cb-4796-993f-5362f76a02ee%2Fwtxyg1v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Quadratic Interpolation
• a strategy for improving the estimate by introducing some
curvature into the line connecting the points. If three data
points are available, this can be accomplished with a
second-order polynomial.
f₂(x) = bo + b₁(x − xo) + b₂(x -xo) (x -x₁)
X
f(x)
0
0
100
400
600
800
1000
200
0.82436 1 0.73576 0.40601 0.19915 0.09158
Find the value of the function at x = 482 using
Quadratic Interpolation
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