Quadratic Form: Vertex: Axis of Symmetry: -8-7 8 4 -1 6 7 8 2 y-intercept: x-intercepts: Domain: Range: 2. Y = -2(x+¹)(X+3)

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Quadratic Function Analysis

#### Given Equation:
\( y = -2(x+1)(x+3) \)

#### Quadratic Form:
The equation is in the factored form. 
\[ y = a(x-r_1)(x-r_2) \]
where \( a = -2 \), \( r_1 = -1 \), and \( r_2 = -3 \).

#### Vertex:
To find the vertex, use the formula to find the x-coordinate:
\[ x = \frac{r_1 + r_2}{2} \]
\[ x = \frac{-1 + (-3)}{2} \]
\[ x = -2 \]

Substituting \( x = -2 \) into the equation to find \( y \):
\[ y = -2(-2+1)(-2+3) \]
\[ y = -2(-1)(1) \]
\[ y = 2 \]

So, the vertex is at \((-2, 2)\).

#### x-intercepts:
The x-intercepts (roots) are the values of \( x \) when \( y = 0 \):
\[ (x+1)(x+3) = 0 \]
So the x-intercepts are \( x = -1 \) and \( x = -3 \).

#### y-intercept:
The y-intercept is the value of \( y \) when \( x = 0 \):
\[ y = -2(0+1)(0+3) \]
\[ y = -2(1)(3) \]
\[ y = -6 \]

So, the y-intercept is at \( y = -6 \).

#### Axis of Symmetry:
The axis of symmetry is the vertical line that passes through the vertex. It can be expressed as:
\[ x = -2 \]

#### Domain:
The domain of the quadratic function is all real numbers:
\[ (-\infty, +\infty) \]

#### Range:
Since the parabola opens downwards (negative coefficient), the range is:
\[ (-\infty, 2] \]

### Graph Explanation:
The graph is a coordinate plane with an x-axis and a y-axis. The x-axis ranges from -10 to 10, and the y-axis ranges from -10 to 10, marked at single unit intervals. The vertex of the parabola should be plotted at \((-2,
Transcribed Image Text:### Quadratic Function Analysis #### Given Equation: \( y = -2(x+1)(x+3) \) #### Quadratic Form: The equation is in the factored form. \[ y = a(x-r_1)(x-r_2) \] where \( a = -2 \), \( r_1 = -1 \), and \( r_2 = -3 \). #### Vertex: To find the vertex, use the formula to find the x-coordinate: \[ x = \frac{r_1 + r_2}{2} \] \[ x = \frac{-1 + (-3)}{2} \] \[ x = -2 \] Substituting \( x = -2 \) into the equation to find \( y \): \[ y = -2(-2+1)(-2+3) \] \[ y = -2(-1)(1) \] \[ y = 2 \] So, the vertex is at \((-2, 2)\). #### x-intercepts: The x-intercepts (roots) are the values of \( x \) when \( y = 0 \): \[ (x+1)(x+3) = 0 \] So the x-intercepts are \( x = -1 \) and \( x = -3 \). #### y-intercept: The y-intercept is the value of \( y \) when \( x = 0 \): \[ y = -2(0+1)(0+3) \] \[ y = -2(1)(3) \] \[ y = -6 \] So, the y-intercept is at \( y = -6 \). #### Axis of Symmetry: The axis of symmetry is the vertical line that passes through the vertex. It can be expressed as: \[ x = -2 \] #### Domain: The domain of the quadratic function is all real numbers: \[ (-\infty, +\infty) \] #### Range: Since the parabola opens downwards (negative coefficient), the range is: \[ (-\infty, 2] \] ### Graph Explanation: The graph is a coordinate plane with an x-axis and a y-axis. The x-axis ranges from -10 to 10, and the y-axis ranges from -10 to 10, marked at single unit intervals. The vertex of the parabola should be plotted at \((-2,
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