Q/Derive from Figure (1) the final equation and law (V4,V5) by assuming given data , the equivalent circuit for a 5- disc string. Let us suppose that self capacitance of each disc is C. Let us further assume that shunt capacitance C, is some fraction K of self capacitance i.e. , C, = KC . Starting from the cross - arm or tower, the volt age across each unit is V1 , V2 ,V3 , V4 and V5 , respectively as shown. Applying Kirchhoff's current law to node A, we get,

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Q/Derive from Figure (1) the
final equation and law (V4,V5)
| by assuming given data , the
equivalent circuit for a 5- disc
string. Let us suppose that
self capacitance of each disc
is C. Let us further assume
that shunt capacitance C, is
| some fraction K of self
capacitance i.e. , C, = KC.
Starting from the cross arm
or tower, the volt age across
each unit is V1, V2 ,V3, V4
and V5 , respectively as
shown . Applying Kirchhoff's
current law to node A, we get,
,ii不1
V5
(fiz 1)
UT
Transcribed Image Text:Q/Derive from Figure (1) the final equation and law (V4,V5) | by assuming given data , the equivalent circuit for a 5- disc string. Let us suppose that self capacitance of each disc is C. Let us further assume that shunt capacitance C, is | some fraction K of self capacitance i.e. , C, = KC. Starting from the cross arm or tower, the volt age across each unit is V1, V2 ,V3, V4 and V5 , respectively as shown . Applying Kirchhoff's current law to node A, we get, ,ii不1 V5 (fiz 1) UT
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