Q/A WTP are to be treated 3800 (m/day) is designed as in items below: a) Rectangular sedimentation tank at detention time 2.5 hr., and the smallest particle to be removed 100% is 0.05 mm in diameter (pw =1000 kg/m³, uw=1.03X10 kg/m.sec., and Gs-1.2). Design the tank dimension (Length L, Width W, and depth H), check the horizontal velocity V, SOR (m/day) and weir loading rate WLR (m/m².day)?. b) One rectangular flocculator at dimension (L=10m, W=5m and H=2m), Gt=3600. Find the velocity gradient in this tank?.

Q/A WTP are to be treated 3800 (m/day) is designed as in items below: a) Rectangular sedimentation tank at detention time 2.5 hr., and the smallest particle to be removed 100% is 0.05 mm in diameter (pw =1000 kg/m³, uw=1.03X10 kg/m.sec., and Gs-1.2). Design the tank dimension (Length L, Width W, and depth H), check the horizontal velocity V, SOR (m/day) and weir loading rate WLR (m/m².day)?. b) One rectangular flocculator at dimension (L=10m, W=5m and H=2m), Gt=3600. Find the velocity gradient in this tank?.

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter2: Origin Of Soil And Grain Size

Section: Chapter Questions

Problem 2.14P: A hydrometer test has the following result: Gs = 2.65, temperature of water = 26 C, and L = 10.4 cm...

See similar textbooks

Similar questions

I need answe of this question please
Design the following items for an aerated grit chamber for the treatment of municipal wastewater. Using two grit chambers. The required data for design is listed in table below. The average flow rate Peaking factor The average detention time at peak flowrate The width: depth ratio Depth Air supply per unit of length Grit quantity per day at peak flow 0.45 m3/s 3 min 1.25: 1.0 3.0 m 0.5 m³/m. min 0.05 m³/103 m³
a. Design a rectangular sedimentation tank to treat 2.4 million litres of raw water per day. Thedetention period may be assumed to be 3 hours. [5]b. Discuss any three types of particle settling in the sedimentation tank. [6]c. Discuss one mechanism of controlling particulate matter. [3]d. Discuss three reasons what determine the location of manholes.
H.W: Design a sedimentation tank to be treat 0.10 m³/sec
Two sedimentation tanks operate in parallel. The combined flow of the tanks is 0.2 m³/s. The depth of each tank is 3 m and each has a detention time of 2 hrs. During the operation, the operator decided to remove particles that having settling velocity of 0.1 mm/s, 0.4 mm/s and 1 mm/s. What is the percentage of removal that should be expected for each particle in an ideal sedimentation tanks.
Design a sedimentation basin for a water treatment plant with the following specifications assuming it is required to supply a city with a population of 50,000 people: Rectangular or square basin • Depth: 7-18 ft ● . • Width: 10-50 ft Detention time: 4-8 hours Flow through velocity: <0.55 ft/min Overflow rate: 400-1,100 gal/day-ft² Draw a figure to show calculated dimensions. You may consider to use SI units in calculations. ● ● Hint: Overflow rate is Flow/Surface Area; Detention time is Volume of tank/Flow rate; and Depth= Volume/Surface area
III. Using Atterberg's Plasticity Determination Method Determinethe following; a) Plot the Flow Curve and b) Determine the Flow Index c) Computethe Liquid Limit d) and if the Plastic Limit wa. uetermined as PL = 17.545 % what is the Plasticity Index ? Number of Blows Moisture Content,% 15 38.589 20 35.712 29 28.556 32 24.670
A rectangular sedimentation tank following coagulation- Exa flocculation is to treat a flow of 3000 m³ / day with a detention time of 6 hours. It is to be hand cleaned of sludge at 6 week intervals. The suspended solids concentration of the water is reduced from 250 mg/L to 5 mg|L by coagulation- flocculation. The settled sludge includes 40 mg/L (based on water flow) of metallic precipitate and has a moisture content of 85% and specific gravity of 1.24. Determine the volume of sludge produced between cleanings and the basic dimensions of the tank if the water depth just before cleaning is 3 m and its length is twice its width.
A municipal wastewater treatment plant employs three circular primary clarifiers arranged in parallel, following the bar screen and grit removal chamber. The plant receives 12 MGD. Each clarifier is center-fed (water enters at the center and exists at the perimeter).The clarifier radius is 56 ft and depth is 10 ft.What is the hydraulic loading rate (critical velocity) in each clarifier in units of ft3.ft-2.hr-1 ?
Question 57
A hydrometer test has the following result: Gs = 2.65, temperature of water = 26 C, and L = 10.4 cm at 45 minutes after the start of sedimentation (see Figure 2.25). What is the diameter D of the smallest-size particles that have settled beyond the zone of measurement at that time (that is, t = 45 min)? Figure 2.25 ASTM 152H type of hydrometer placed inside the sedimentation cylinder (Courtesy of Khaled Sobhan, Florida Atlantic University, Boca Raton, Florida)
A rectangular sedimentation tank is designed with a depth of 3.5 mand a detention time of 1 h. Is the design suffcient to achieve complete removal of particles with a diameter of 0.01 mm? Specifc gravity of the particles is 2.65. The fow rate and temperature of waterare 10,000 m3/d and 20°C, respectively. At 20°C, density of water is998 kg/m3 and dynamic viscosity of water is 10–3 kg/m·s. State anyassumptions you make to calculate your results.