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Q9. For a portfolio of fully discrete 40-year endowment insurances of 1 on independent lives age x, you are given: The premium mistakenly charged is the benefit premium for a fully discrete 40- year term insurance of 1 on (x). L is the loss-at-issue random variable for one policy. A₁ = 0.257 - X:40] Ax:401 = 0.268 2AX:40 = 0.0745 d = 0.05 By using the normal approximation, calculate the number of policies the insurer must issue so that the probability of a positive aggregate loss on the policies issued is 95%. -

Q9. For a portfolio of fully discrete 40-year endowment insurances of 1 on independent lives age x, you are given: The premium mistakenly charged is the benefit premium for a fully discrete 40- year term insurance of 1 on (x). L is the loss-at-issue random variable for one policy. A₁ = 0.257 - X:40] Ax:401 = 0.268 2AX:40 = 0.0745 d = 0.05 By using the normal approximation, calculate the number of policies the insurer must issue so that the probability of a positive aggregate loss on the policies issued is 95%. -

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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For a portfolio of fully discrete 40-year endowment insurances of 1 on independent lives age x, you are given: The premium mistakenly charged is the benefit premium for a fully discrete 40- year term insurance of 1 on (x). L is the loss-at-issue random variable for one policy. A₁ = 0.257 x:40 Ax:401 = 0.268 2Ax:401 d = 0.05 By using the normal approximation, calculate the number of policies the insurer must issue so that the probability of a positive aggregate loss on the policies issued is 95%. = 0.0745
Transcribed Image Text:For a portfolio of fully discrete 40-year endowment insurances of 1 on independent lives age x, you are given: The premium mistakenly charged is the benefit premium for a fully discrete 40- year term insurance of 1 on (x). L is the loss-at-issue random variable for one policy. A₁ = 0.257 x:40 Ax:401 = 0.268 2Ax:401 d = 0.05 By using the normal approximation, calculate the number of policies the insurer must issue so that the probability of a positive aggregate loss on the policies issued is 95%. = 0.0745
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