**Q9: Voxelotor's structure is shown below. What would you expect the overall charge of the molecule to be in the blood (pH = 7.4)?**- Pyridinium pKa = 2.6- Phenol pKa = 8.3The image displays the chemical structure of Voxelotor:- The central structure features a bicyclic aromatic ring containing nitrogen atoms, indicating a pyridinium moiety.- Connected to the pyridinium ring is a phenol group, characterized by a hydroxyl (-OH) group bonded to an aromatic ring.**Explanation:**In the context of blood at physiological pH (7.4), the following considerations apply:- **Pyridinium Group:** With a pKa of 2.6, this group will likely be protonated at pH 7.4, as the pH is higher than the pKa. This would impart a positive charge to the molecule. - **Phenol Group:** With a pKa of 8.3, this group will largely remain un-ionized at pH 7.4, as the pH is below the pKa. Thus, it is likely to remain neutral.Overall, the molecule would likely have a positive charge under physiological conditions due to the protonation of the pyridinium group.

Answered: Image /qna-images/answer/33427b4f-1d87-4192-869b-8d5ec68f12d9.jpg

Answered: Q9: Voxelotor's structure is shown…

Q9: Voxelotor's structure is shown below. What would you expect the overall charge of the molecule to be in the blood (pH = 7.4) Pyridinium pka = 2.6 Phenol pka = 8.3 H. N OH N'

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Question

**Q9: Voxelotor's structure is shown below. What would you expect the overall charge of the molecule to be in the blood (pH = 7.4)?**

- Pyridinium pKa = 2.6
- Phenol pKa = 8.3

The image displays the chemical structure of Voxelotor:

- The central structure features a bicyclic aromatic ring containing nitrogen atoms, indicating a pyridinium moiety.
- Connected to the pyridinium ring is a phenol group, characterized by a hydroxyl (-OH) group bonded to an aromatic ring.

**Explanation:**

In the context of blood at physiological pH (7.4), the following considerations apply:

- **Pyridinium Group:** With a pKa of 2.6, this group will likely be protonated at pH 7.4, as the pH is higher than the pKa. This would impart a positive charge to the molecule.

- **Phenol Group:** With a pKa of 8.3, this group will largely remain un-ionized at pH 7.4, as the pH is below the pKa. Thus, it is likely to remain neutral.

Overall, the molecule would likely have a positive charge under physiological conditions due to the protonation of the pyridinium group.

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