Q7. What is the mole fraction of B at equilibrium when 0.16 mole of A and 0.18 mole of B are placed on 2 L of a container and allowed to reach the equilibrium at 864 K? A(8) +B(s)2Cg) +D Kp =3.54 at 864 K

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
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Chapter12: Chemical Equilibrium
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Q7. What is the mole fraction of B at equilibrium when 0.16 mole of A and 0.18 mole of B are
placed on 2 L of a container and allowed to reach the equilibrium at 864 K?
A(8)
+B(s)2Cg) +D Kp =3.54 at 864 K
Transcribed Image Text:Q7. What is the mole fraction of B at equilibrium when 0.16 mole of A and 0.18 mole of B are placed on 2 L of a container and allowed to reach the equilibrium at 864 K? A(8) +B(s)2Cg) +D Kp =3.54 at 864 K
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