Q7) The current in(t) of Fig. 4 can be found as (mA):a) 12.5cos(500t - 0.107°)d) 12.5 cos(500t + 89.9°)2cos101 V2000www40HEEpab) 12.5cos(500t+ 0.107°)e) 12.5 cos(500t +0.205°)10.025 cos 10rV20:271502Fig. 3100c) 12.5cos(500t - 89.9°)f) 12.5 cos(500t - 0.205°)cos5001 V1002www0.211Fig. 40.3mH

Given, The circuit shown in figure 4 is shown below,

Q7) The current i(t) of Fig. 4 can be found as (mA): a) 12.5cos(500t - 0.107°) d) 12.5 cos(500t + 89.9°) 2cas101 V 2000 www 40 HF 20 b) 12.5cos(500t+ 0.107°) e) 12.5 cos(500t +0.205°) 10-52 5 cos 10rV 2052 WY Z 74502 Fig. 3 c) 12.5cos(500t - 89.9°) f) 12.5 cos(500t - 0.205°) 10052 10 cos5001 V 0.2 i Fig. 4 0,3 m

Q7) The current i(t) of Fig. 4 can be found as (mA): a) 12.5cos(500t - 0.107°) d) 12.5 cos(500t + 89.9°) 2cas101 V 2000 www 40 HF 20 b) 12.5cos(500t+ 0.107°) e) 12.5 cos(500t +0.205°) 10-52 5 cos 10rV 2052 WY Z 74502 Fig. 3 c) 12.5cos(500t - 89.9°) f) 12.5 cos(500t - 0.205°) 10052 10 cos5001 V 0.2 i Fig. 4 0,3 m

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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