Q7: For the circuit shown, find Rand the power in 10 Ohmresistance1510A 215wwR41.5 A20 VR= 8 Ohm P= 22.5 mwR= 6 Ohm P= 2.25 wnone of the mentionedR= 15 Ohm P= 22.5 wR= 6 Ohm P= 22.5 w

Solution: The modified circuit is,

Q7: For the circuit shown, find R and the power in 10 Ohm resistance 15 10 15 ww I3 ww R 41.5 A 20 V R= 8 Ohm P= 22.5 mw R= 6 Ohm P= 2.25 w none of the mentioned O R= 15 Ohm P= 22.5 w R= 6 Ohm P= 22.5 w B.

Q7: For the circuit shown, find R and the power in 10 Ohm resistance 15 10 15 ww I3 ww R 41.5 A 20 V R= 8 Ohm P= 22.5 mw R= 6 Ohm P= 2.25 w none of the mentioned O R= 15 Ohm P= 22.5 w R= 6 Ohm P= 22.5 w B.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Current Division Method

The generalized current divider formula is given by the following relation below,

Question

Q7: For the circuit shown, find R
and the power in 10 Ohm
resistance
15
10
A 2
15
ww
R
41.5 A
20 V
R= 8 Ohm P= 22.5 mw
R= 6 Ohm P= 2.25 w
none of the mentioned
R= 15 Ohm P= 22.5 w
R= 6 Ohm P= 22.5 w

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