Q7: Calculate the mean activity coefficient as predicted by the Debye-Huckel Limiting Law (DHLL) for the ions of a 0.40 M aqueous solution of NaCl at 298 K. b) 0.320 c) 0.477 d) 0.250 a) 0.592 e) 1.82

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physical chemistry, please solve question 7

25: What is the concentration of Al(NO3)3 that have ionic strength equals 0.0066?
b) 0.051 M
a) 1.1×10-³ M
c) 0.033 M
d) 0.017 M
e) 0.10 M
26: The solubility of AgCl in water will increase in which of the following cases?
a) Adding some HCl
b) Adding more AgCl(s)
c) By decreasing the ionic strength
d) Solubility is constant and does not change
e) Adding small amount of Mg(NO3)2
Q7: Calculate the mean activity coefficient as predicted by the Debye-Huckel Limiting Law
(DHLL) for the ions of a 0.40 M aqueous solution of NaCl at 298 K.
a) 0.592
b) 0.320
c) 0.477
d) 0.250
Q8: Calculate the emf of the cell: Zn/Zn²+ (0.001 M) || Agt (0.01 M)|Ag at 25°C.
Given: Zn²+ + 2e → Zn
E-0.760 V
Ag + e
→ Ag
E= +0.800 V
b) 1.59 V
a) 1.63 V
a) 6×10+5
c) 1.07 V
b) 9×10+3
Q9: What is the approximate equilibrium constant at 25°C for the reaction 2 Cut → Cu²+ + Cu?
Given: Cu²+ +eCut E-0.159 V
Cute → Cu E=0.520 V
c) 1×10+6
d) 1.81 V
Q10: The values of the rate constant for the reaction
e) 1.82
d) 3×10 +7
e) 1.53 V
e) 4x10+4
2 N₂O5(g) →4 NO2(g) + O2(g)
were determined at several temperatures. A plot of (In k) versus (1/T) gave a straight line of which
the slope was found to be -1.2×105 K. What is the activation energy of the reaction in kJ/mol?
a) 1.0×10+3
b) 1.0×10+2
c) 1.0×10+5
d) 1.0×10+4
e) 1.0×10+6
Transcribed Image Text:25: What is the concentration of Al(NO3)3 that have ionic strength equals 0.0066? b) 0.051 M a) 1.1×10-³ M c) 0.033 M d) 0.017 M e) 0.10 M 26: The solubility of AgCl in water will increase in which of the following cases? a) Adding some HCl b) Adding more AgCl(s) c) By decreasing the ionic strength d) Solubility is constant and does not change e) Adding small amount of Mg(NO3)2 Q7: Calculate the mean activity coefficient as predicted by the Debye-Huckel Limiting Law (DHLL) for the ions of a 0.40 M aqueous solution of NaCl at 298 K. a) 0.592 b) 0.320 c) 0.477 d) 0.250 Q8: Calculate the emf of the cell: Zn/Zn²+ (0.001 M) || Agt (0.01 M)|Ag at 25°C. Given: Zn²+ + 2e → Zn E-0.760 V Ag + e → Ag E= +0.800 V b) 1.59 V a) 1.63 V a) 6×10+5 c) 1.07 V b) 9×10+3 Q9: What is the approximate equilibrium constant at 25°C for the reaction 2 Cut → Cu²+ + Cu? Given: Cu²+ +eCut E-0.159 V Cute → Cu E=0.520 V c) 1×10+6 d) 1.81 V Q10: The values of the rate constant for the reaction e) 1.82 d) 3×10 +7 e) 1.53 V e) 4x10+4 2 N₂O5(g) →4 NO2(g) + O2(g) were determined at several temperatures. A plot of (In k) versus (1/T) gave a straight line of which the slope was found to be -1.2×105 K. What is the activation energy of the reaction in kJ/mol? a) 1.0×10+3 b) 1.0×10+2 c) 1.0×10+5 d) 1.0×10+4 e) 1.0×10+6
Expert Solution
Step 1

Question 7:

Molarity of NaCl = 0.40 M

Temperature = 298 K

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