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Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Q6//The farm shown in the figure is irrigated by furrow system: . FC-32% by vol. ,W P= 18% by vol. • PAD=70% • Depth of root zone=100 cm . • Spacing between furrows = 80 cm The field is irrigated 2 days in week • Total available discharge Q₁-60 Lps • Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m 0.5%

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Q6//The farm shown in the figure is irrigated by furrow system: • FC=32% by vol. ,W P = 18% by vol. . PAD= 70% • Depth of root zone-100 cm • • • • Spacing between furrows = 80 cm The field is irrigated 2 days in week Total available discharge Qa= 60 Lps Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m + 0.5%
Transcribed Image Text:Q6//The farm shown in the figure is irrigated by furrow system: • FC=32% by vol. ,W P = 18% by vol. . PAD= 70% • Depth of root zone-100 cm • • • • Spacing between furrows = 80 cm The field is irrigated 2 days in week Total available discharge Qa= 60 Lps Discharge of one furrow.q=1.0 Lps Neglect any service area, calculate: a) length of one furrow and their total number b) number of furrows irrigated at the same time and number of irrigation groups c) application time of any group d) net irrigation depth el application efficiency 0.1% 288m ↑ 200m + 0.5%
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