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Q6. The magnetic circuit shown in Figure Q6 is made of high permeability material so that its reluctance can be negligible. The dimensions are as follows: N= 1250 turns, a = 16 cm, b = 6 cm, c = 5 cm, d= 2 mm, and i = 16 Adc. (i) Write an expression for the area normal to the flux, 4g, and the volume of the air gap, Vz- (ii) Obtain an expression for the energy, W, as a function of magnetic flux density, B, magnetic circuit dimensions, and magnetic field quantities. Then, obtain W; as a function of 2 and x. (iii) Obtain an expression for the coenergy, W' as a function of magnetic field strength, H, magnetic circuit dimensions, and other magnetic field quantities. Then, obtain W; as a function of i and x.

Q6. The magnetic circuit shown in Figure Q6 is made of high permeability material so that its reluctance can be negligible. The dimensions are as follows: N= 1250 turns, a = 16 cm, b = 6 cm, c = 5 cm, d= 2 mm, and i = 16 Adc. (i) Write an expression for the area normal to the flux, 4g, and the volume of the air gap, Vz- (ii) Obtain an expression for the energy, W, as a function of magnetic flux density, B, magnetic circuit dimensions, and magnetic field quantities. Then, obtain W; as a function of 2 and x. (iii) Obtain an expression for the coenergy, W' as a function of magnetic field strength, H, magnetic circuit dimensions, and other magnetic field quantities. Then, obtain W; as a function of i and x.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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Q6. The magnetic circuit shown in Figure Q6 is made of high permeability material so that its reluctance can be negligible. The dimensions are as follows: N= 1250 turns, a = 16 cm, b = 6 cm, c = 5 cm, d = 2 mm, and i = 16 Adc. (i) Write an expression for the area normal to the flux, Ag, and the volume of the air gap, Vg. (ii) Obtain an expression for the energy, W; as a function of magnetic flux density, B, magnetic circuit dimensions, and magnetic field quantities. Then, obtain W; as a function of i and x. (iii) Obtain an expression for the coenergy, W' as a function of magnetic field strength, H, magnetic circuit dimensions, and other magnetic field quantities. Then, obtain Ws as a function of i and x. (iv) Obtain an expression for the inductance, L as a function of r. (v) Find an expression for the force, fm, on the moveable part using (ii), (iii) and (iv). Calculate the force, fm at x= 2 mm and show that the obtained results are the same. (vi) If the maximum flux density, Bmax, is to be limited to 1.5 T, determine fm(max).
Transcribed Image Text:Q6. The magnetic circuit shown in Figure Q6 is made of high permeability material so that its reluctance can be negligible. The dimensions are as follows: N= 1250 turns, a = 16 cm, b = 6 cm, c = 5 cm, d = 2 mm, and i = 16 Adc. (i) Write an expression for the area normal to the flux, Ag, and the volume of the air gap, Vg. (ii) Obtain an expression for the energy, W; as a function of magnetic flux density, B, magnetic circuit dimensions, and magnetic field quantities. Then, obtain W; as a function of i and x. (iii) Obtain an expression for the coenergy, W' as a function of magnetic field strength, H, magnetic circuit dimensions, and other magnetic field quantities. Then, obtain Ws as a function of i and x. (iv) Obtain an expression for the inductance, L as a function of r. (v) Find an expression for the force, fm, on the moveable part using (ii), (iii) and (iv). Calculate the force, fm at x= 2 mm and show that the obtained results are the same. (vi) If the maximum flux density, Bmax, is to be limited to 1.5 T, determine fm(max).
depth = c a Frictionless nonmagnetic sleeve with permeability uo- and thickness d
Transcribed Image Text:depth = c a Frictionless nonmagnetic sleeve with permeability uo- and thickness d
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