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Q6. Find the center of mass of the lamina corresponding to the parabolic region 0 ≤ y ≤ 4- x² where the density at the point (x, y) is proportional to the distance between (x, y) and the x - axis as shown in the figure below. Variable density: p(x, y) = ky y=4-x² <-2 (x, y) Parabolic region of variable density

Q6. Find the center of mass of the lamina corresponding to the parabolic region 0 ≤ y ≤ 4- x² where the density at the point (x, y) is proportional to the distance between (x, y) and the x - axis as shown in the figure below. Variable density: p(x, y) = ky y=4-x² <-2 (x, y) Parabolic region of variable density

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Q6. Find the center of mass of the lamina corresponding to the parabolic region 0 ≤ y ≤ 4- x² where the density at the point (x, y) is proportional to the distance between (x, y) and the x - axis as shown in the figure below. Variable density: p(x, y) = ky y=4-x² <-2 (x, y) Parabolic region of variable density
Transcribed Image Text:Q6. Find the center of mass of the lamina corresponding to the parabolic region 0 ≤ y ≤ 4- x² where the density at the point (x, y) is proportional to the distance between (x, y) and the x - axis as shown in the figure below. Variable density: p(x, y) = ky y=4-x² <-2 (x, y) Parabolic region of variable density
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