Q6 )The following processes are submitted to an operating system. They are calculation processeswhich require no input/output (i.e. they are always ready to utilize the CPU)1. Draw Gantt charts that illustrate the execution of these processes using the following schedulingalgorithms: FCFS, Preemptive and non preemptive SJF, preemptive and nonpreemptivepriority, Highest response ratio next (HRRN), and RR (quantum = 2).2.What is the average turnaround time average waiting time, schedule length, and throughputof each process for each of the scheduling algorithms in part 1?3. Which of the algorithms results in the minimum average waiting time (over all processes)? (1. FCFSPID AT BT0P18P26P3P4P5PlP2P32. Non-Preemptive SJFPID AT BT CT TAT082211933Gantt Chart:61P419P5 3 3Gantt Chart:.2.23. Preemptive SJFPIDPLP2P31P41 9PS 3 3Gantt Chart:BT0 8126AT2CT TAT WTCTΤΑΊWTWTAverage Turnaround Time-Average Waiting time =Schedule Length-Throughtput-.Average Turnaround Time=Average Waiting timeSchedule Length=ThroughputAverage Turnaround Time. Average Waiting time-Schedule Length=Throughtpat

1.FCFS NON-PREEMTIVE: Which means that if the process get started for execution it never ended until…

Q6 )The following processes are submitted to an operating system. They are calculation processes which require no input/output (i.e. they are always ready to utilize the CPU) 1. Draw Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, Preemptive and non preemptive SJF, preemptive and nonpreemptive priority, Highest response ratio next (HRRN), and RR (quantum-2). 2. What is the average turnaround time average waiting time, schedule length, and throughput of each process for each of the scheduling algorithms in part 17 3. Which of the algorithms results in the minimum average waiting time (over all processes)? ( 1. FCFS PID AT BT PI 0 S P2 2 . P3 P4 P5 . 2 P3 2 P4 1 PS 3 2 1 3 Gantt Chart: 2. Non-Preemptive SJF PID AT BT CT TAT WT 0 S Pl P2 6 HERREX PID AT PI 0 3 Gantt Chart: . P2 2 61 3. Preemptive SJF P3 2 P4 1 PS 3 9 6 1 BT 8 6 1 9 3 9 3 Gantt Chart: CT TAT WT CT TAT WT . . Average Turnaround Time- Average Waiting time => Schedule Length- Throughtput- Average Turnaround Time= Average Waiting time - Schedule Length= Throughput Average Turnaround Time Average Waiting time- Schedule Length Throughtpat-

Q6 )The following processes are submitted to an operating system. They are calculation processes which require no input/output (i.e. they are always ready to utilize the CPU) 1. Draw Gantt charts that illustrate the execution of these processes using the following scheduling algorithms: FCFS, Preemptive and non preemptive SJF, preemptive and nonpreemptive priority, Highest response ratio next (HRRN), and RR (quantum-2). 2. What is the average turnaround time average waiting time, schedule length, and throughput of each process for each of the scheduling algorithms in part 17 3. Which of the algorithms results in the minimum average waiting time (over all processes)? ( 1. FCFS PID AT BT PI 0 S P2 2 . P3 P4 P5 . 2 P3 2 P4 1 PS 3 2 1 3 Gantt Chart: 2. Non-Preemptive SJF PID AT BT CT TAT WT 0 S Pl P2 6 HERREX PID AT PI 0 3 Gantt Chart: . P2 2 61 3. Preemptive SJF P3 2 P4 1 PS 3 9 6 1 BT 8 6 1 9 3 9 3 Gantt Chart: CT TAT WT CT TAT WT . . Average Turnaround Time- Average Waiting time => Schedule Length- Throughtput- Average Turnaround Time= Average Waiting time - Schedule Length= Throughput Average Turnaround Time Average Waiting time- Schedule Length Throughtpat-

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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COURSE Operating System Only correct answer will be upvoted. Else downvoted.
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Question 16 Rk.use python Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line