I’m having difficulty time comprehending this problem. The solution is giving but could you explain in detail how to do each part. Please explain where everything came from graphs, numbers, and etc. **Question 6:** Draw the influence line for the force in (a) member JI, (b) member IE, and (c) member EF.**Solution****Diagram Explanation:**This image contains a truss structure diagram and three separate influence line graphs associated with different truss members.**Truss Diagram:**- The truss is a symmetrical arrangement consisting of seven joints (A to G) connected by horizontal members, each measuring 6 feet, with a total span of 36 feet. The height of the truss is 8 feet at its tallest points (L and J).- The joints are labeled: L, K, J, I, H on the top and A, B, C, D, E, F, G at the bottom.**Influence Line Graphs:**1. **For Member JI:** - Horizontal axis: \( x \) in feet, ranging from 0 to 36 feet. - Vertical axis: Force \( F_{JI} \). - The line starts at 0, decreases linearly to \(-0.25\) at 6 feet, \(-0.5\) at 18 feet, reaches \(-1\) at 24 feet, then increases back symmetrically.2. **For Member IE:** - Horizontal axis: \( x \) in feet, ranging from 0 to 36 feet. - Vertical axis: Force \( F_{IE} \). - The graph begins at 0, increases linearly, hitting 0.167 at 6 feet, 0.333 at 12 feet, and peaking at 0.667 at 24 feet. - It then drops back, becoming negative at \(-0.167\) by 30 feet.3. **For Member EF:** - Horizontal axis: \( x \) in feet, ranging from 0 to 36 feet. - Vertical axis: Force \( F_{EF} \). - Starts at 0, increases linearly, reaching a peak value of 1 at 24 feet before symmetrically returning to 0.These influence lines help in determining how different points along the truss affect the forces in these specified members.

Answered: Image /qna-images/answer/c0f1149c-b663-458d-9d4b-141f849a9d2c.jpg

Q6 Draw the influence line for the force in (a) member JI, (b) member IE, and (c) member EF. L K J 1 H Solution 51 6 72- 18 24 30 36 -0.25 -0.5 -x(ft) -0.5 B -6-1-6- 6ft 6ft E -6 ft -0.75 -1 FEF FIE 0-75 0.5 0.667 02 0.5 0.5 .... 1. 0.333 0-167 30 36 6 12 18 36 24 30 —x(A) 6 2 18 24 -0.167 28.8 6ft +x(ft) 8 ft

Q6 Draw the influence line for the force in (a) member JI, (b) member IE, and (c) member EF. L K J 1 H Solution 51 6 72- 18 24 30 36 -0.25 -0.5 -x(ft) -0.5 B -6-1-6- 6ft 6ft E -6 ft -0.75 -1 FEF FIE 0-75 0.5 0.667 02 0.5 0.5 .... 1. 0.333 0-167 30 36 6 12 18 36 24 30 —x(A) 6 2 18 24 -0.167 28.8 6ft +x(ft) 8 ft

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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