Q6 Consider a plane surface in a uniform electric field as E in Figure P24.48, where d 15.0 cm and 0 = 70.0°. If the %3D net flux through the surface is 6.00 N · m²/C, find the mag- d nitude of the electric field. Figure P24.48 Find the electric flux through the plane surface shown in Figure P24.48 if 0 = 60.0°, E = 350 N/C, and d = %3D %3D 5.00 cm. The electric field is uniform over the entire area of the surface.
Q6 Consider a plane surface in a uniform electric field as E in Figure P24.48, where d 15.0 cm and 0 = 70.0°. If the %3D net flux through the surface is 6.00 N · m²/C, find the mag- d nitude of the electric field. Figure P24.48 Find the electric flux through the plane surface shown in Figure P24.48 if 0 = 60.0°, E = 350 N/C, and d = %3D %3D 5.00 cm. The electric field is uniform over the entire area of the surface.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
Related questions
Question

Transcribed Image Text:Consider a plane surface in
a uniform electric field as
Q6
E
in Figure P24.48, where d =
15.0 cm and 0 = 70.0°. If the
net flux through the surface is
6.00 N · m²/C, find the mag-
d
nitude of the electric field.
Figure P24.48
Find the electric flux through
the plane surface shown
in Figure P24.48 if 0 = 60.0°, E = 350 N/C, and d =
%3D
5.00 cm. The electric field is uniform over the entire
area of the surface.
Expert Solution

Step 1By
6)
Flux = Ed2Cos70°
E = 6/(.152×Cos70°)
E = 779.68 N/C
7) Flux = Ed2 Cos70°
= 350×.152×Cos70°
= 2.69 N-m2/C
Step by step
Solved in 2 steps
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