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Q6 Connected Components Suppose G is a connected graph. You want to know how many connected components the graph will have if node v is removed – call this number f(v). Which of the following is true? O f(v) is equal to the degree of v in G O f(v) is equal to the number of children of v in the DFS tree started at v O f(v) is equal to the number of children if v in the BFS tree started at v None of the above

Q6 Connected Components Suppose G is a connected graph. You want to know how many connected components the graph will have if node v is removed – call this number f(v). Which of the following is true? O f(v) is equal to the degree of v in G O f(v) is equal to the number of children of v in the DFS tree started at v O f(v) is equal to the number of children if v in the BFS tree started at v None of the above

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Q6 Connected Components Suppose G is a connected graph. You want to know how many connected components the graph will have if node v is removed – call this number f(v). Which of the following is true? O f(v) is equal to the degree of v in G O f(v) is equal to the number of children of v in the DFS tree started at v f(v) is equal to the number of children if v in the BFS tree started at v None of the above
Transcribed Image Text:Q6 Connected Components Suppose G is a connected graph. You want to know how many connected components the graph will have if node v is removed – call this number f(v). Which of the following is true? O f(v) is equal to the degree of v in G O f(v) is equal to the number of children of v in the DFS tree started at v f(v) is equal to the number of children if v in the BFS tree started at v None of the above
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