Q6: A digital computer has a memory unit with 24 bits per word. The instruction set consists of 110 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. (a) How many bits are needed for the opcode? (b) How many bits are left for the address part of the instruction? (c) What is the maximum allowable size for memory? (d) Can we extend this instruction set by adding new 10 instructions and keeping the same length of opcode part? (e) Determine the type of this instruction set: stack-based ISA or accumulator- based ISA or general purpose registers-based ISA?
Q6: A digital computer has a memory unit with 24 bits per word. The instruction set consists of 110 different operations. All instructions have an operation code part (opcode) and an address part (allowing for only one address). Each instruction is stored in one word of memory. (a) How many bits are needed for the opcode? (b) How many bits are left for the address part of the instruction? (c) What is the maximum allowable size for memory? (d) Can we extend this instruction set by adding new 10 instructions and keeping the same length of opcode part? (e) Determine the type of this instruction set: stack-based ISA or accumulator- based ISA or general purpose registers-based ISA?
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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