Q5. The 9-kg ball is connected to a spring with spring constant k = 240 N/m and unstretched length of 0.8 m. Initially the spring is compressed and has length 0.5 m. Then under the constant applied force F= 200 N (in the direction shown in the image) acting on the ball, the spring is stretched to a new length 1.5 m. Determine the work done by weight to the ball during this process. The slope is smooth. Please pay attention: the numbers may change since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 1 place after the decimal point, and proper Sl unit. Take g = 9.81 m/s².
Q5. The 9-kg ball is connected to a spring with spring constant k = 240 N/m and unstretched length of 0.8 m. Initially the spring is compressed and has length 0.5 m. Then under the constant applied force F= 200 N (in the direction shown in the image) acting on the ball, the spring is stretched to a new length 1.5 m. Determine the work done by weight to the ball during this process. The slope is smooth. Please pay attention: the numbers may change since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 1 place after the decimal point, and proper Sl unit. Take g = 9.81 m/s².
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![**Question 5:**
The 9-kg ball is connected to a spring with a spring constant \( k = 240 \, \text{N/m} \) and an unstretched length of 0.8 m. Initially, the spring is compressed and has a length of 0.5 m. Then under the constant applied force \( F = 200 \, \text{N} \) (in the direction shown in the image) acting on the ball, the spring is stretched to a new length of 1.5 m. Determine the work done by the **weight** to the ball during this process. The slope is smooth. Please pay attention: **the numbers may change** since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 1 place after the decimal point, and proper SI unit. Take \( g = 9.81 \, \text{m/s}^2 \).
### Diagram Description:
The diagram shows a spring connected to a 9-kg ball on an inclined slope. The slope forms an angle of \( 40^\circ \) with the horizontal. The applied force \( F \) of 200 N is shown acting on the ball at an angle of \( 15^\circ \) from the vertical.
### Input Box:
- **Your Answer:** [ Answer ] [ units ]
Please note, values such as force, spring constant, and gravitational acceleration are critical for calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe7171e53-5d05-46c4-abbf-3d7ddeb936a7%2Fc2d17479-2bce-4ff9-b589-5646db823e32%2F6g0849i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 5:**
The 9-kg ball is connected to a spring with a spring constant \( k = 240 \, \text{N/m} \) and an unstretched length of 0.8 m. Initially, the spring is compressed and has a length of 0.5 m. Then under the constant applied force \( F = 200 \, \text{N} \) (in the direction shown in the image) acting on the ball, the spring is stretched to a new length of 1.5 m. Determine the work done by the **weight** to the ball during this process. The slope is smooth. Please pay attention: **the numbers may change** since they are randomized. Negative sign must be included if the work done is negative. Your answer must include 1 place after the decimal point, and proper SI unit. Take \( g = 9.81 \, \text{m/s}^2 \).
### Diagram Description:
The diagram shows a spring connected to a 9-kg ball on an inclined slope. The slope forms an angle of \( 40^\circ \) with the horizontal. The applied force \( F \) of 200 N is shown acting on the ball at an angle of \( 15^\circ \) from the vertical.
### Input Box:
- **Your Answer:** [ Answer ] [ units ]
Please note, values such as force, spring constant, and gravitational acceleration are critical for calculations.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
The sine component of the weight parallel to the inclined plane is responsible for the work done.
Accordingly,
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Solved in 2 steps with 2 images
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