Q5. Explain why when D is tangential to the surface, D.ds = O. * Because of the boundary condition between a dielectric surface to charged surface has no tangential component Because Gauss's law is an alternative formulation to obtain electric flux density and electric field intensity by the relation with electric charge Because of Divergence theorem and Stoke theorem prove so Because when D only has normal component for charge surface

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Q5. Explain why when D is tangential to the surface, D.ds = O. *
Because of the boundary condition between a dielectric surface to charged surface
has no tangential component
Because Gauss's law is an alternative formulation to obtain electric flux density and
electric field intensity by the relation with electric charge
Because of Divergence theorem and Stoke theorem prove so
Because when D only has normal component for charge surface
Transcribed Image Text:Q5. Explain why when D is tangential to the surface, D.ds = O. * Because of the boundary condition between a dielectric surface to charged surface has no tangential component Because Gauss's law is an alternative formulation to obtain electric flux density and electric field intensity by the relation with electric charge Because of Divergence theorem and Stoke theorem prove so Because when D only has normal component for charge surface
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