Q5. A bag contains 9 white balls and 6 black balls. If a ball is chosen without looking, what is the probability that the ball will be black? a) 0.4 b) 0.5 c) 0.6 d) 0.9 Q6. The box and whisker diagram below indicates that the distribution of the data is: a) Negatively skewed b) Symmetrically distributed c) Positively skewed

Q: 2p=18

A:

Q: 103= 10%3D 2.

A: 102  = 100

Q: -6n-2n=16

A: NOTE: Refresh your page if you can't see any equations. . the given expression is

Q: b- 4b+4 0

A:

Q: 9w2=12w+5

A:

Q: k2-35=2k

A:

Q: -5 • -1/7 • 4/8

A: Refer to the we have to find the product of the -5 • -1/7 • 4/8

Q: The product of 4 and n is -48

A: The product of 4 and n is -48

Q: -2d+1=9

A:

Q: 32+4 to Le

A:

Q: 1+2x=77

A:

Q: 125=252h+1

A: GIVEN: The equation125=252h+1 CALCULATION: We have to find the value of h. The given can be written…

Q: 14 +2

A: Adding Fractions Step 1: Make sure the bottom numbers (the denominators) are the same. Step 2: Add…

Q: 23-8K

A:

Q: 25x4y2 − 36

A: This is is simple factorization question  Formula used (a2-b2)=(a+b)(a-b)

Q: Todt 5(-37+4)

A: Given,   ∫  -3t+410dt

Q: 1 +1

A: Given  1+1=

Q: -3w+5=23

A:

Q: +100 3

A: Our objective is to find the solution of the above expression.

Q: 5y + 6(1-3)=15

A: Answer y = 3  solution is given in step 2

Q: 3=6

A: Suppose the empty box has value x than do the calculation.

Q: 16+29

A: Given :16+29

Q: Ys+1 s7105 +?4

A:

Q: Vs-+ 12²

A: To determine:

Q: -4d = -64

A: Given  -4d=-64

Q: 2(a+3)= -12

A: Solution: Here 2(a+3) =-12

Q: 1+n=15

A: -1+n=15

Q: 12

A: Explanation and solutions is given below....

Q: 8P4 11C7

A:

Q: 10 = 2(p + -4)

A: Given  10 = 2(p + -4) p =?

Q: Find the value of above combination

A:

Q: -5,4y+14-2y=4

A: Given ,  4y + 14 - 2y = 4     ....... (1)  We have to find value of y  (1) implies

Q: 7k = 91

A: We will find the value of k in the following step.

Q: 6+197

A: Given,          6+197

Q: Find L s²-8

A:

Q: a+10+44=2a

A: Simplify L.H.S and then re aggrange like terms on one side and other terms on R.HS.and then…