Q5) Compute the output y(t) of the systems below. In all cases, consider the system with zero initial conditions. TIP: use the convolution table and remember the properties of convolution. a) h(t) = 3 exp(-2t) u(t) and input x(t) = 2 exp(-2t) u(t) Q5.) a) h(t) = 3 exp(-2t) u(t) and input x(t) = 2 exp(-2t) u(t) (A) conv(x(t),h(t)) = 6*t*exp(-2*t)*u(t) (B) conv(x(t),h(t)) = t*exp(-t)*u(t) C) conv(x(t),h(t)) = 2*t*exp(-t)*u(t) (D) conv(x(t),h(t)) = 5*exp(-2*t)*u(t) b) h(t) = 28(t)- 4 exp(-3t) u(t) and input x(t) = 3 u(t) Q5.) b) h(t) = 28(t) - 4 exp(-3t) u(t) and input x(t) = 3 u(t) A) conv(x(t),h(t)) = u(t) + 2*(1-exp(-3*t))*u(t) (B) conv(x(t),h(t)) = 7*u(t) + 9*(1-exp(-3*t))*u(t) C) conv(x(t),h(t)) = 4*u(t)- (1-exp(-3*t))*u(t) (D) conv(x(t),h(t)) = 6*u(t) - 4*(1-exp(-3*t))*u(t) c) h(t) = 2 exp(-t) u(t) and input x(t) = 4 exp(-2t) cos(3t) u(t) Q5.) c) h(t) = 2 exp(-t) u(t) and input x(t) = 4 exp(-2t) cos(3t) u(t) (A) conv(x(t),h(t)) = 6*[0.1*exp(-3*t) - 0.6*exp(-2*t)*cos(3*t+71.56°)]*u(t) B) conv(x(t),h(t)) = [0.2*exp(-t) - 0.125*exp(-2*t)*cos(3*t+71.56°)]*u(t) (C) conv(x(t),h(t)) = 8*[0.1*exp(-t) - 0.316*exp(-2*t)*cos(3*t+71.56°)]*u(t) (D) conv(x(t),h(t)) = 8*[0.1*exp(-t) - 0.316*exp(-t)*sin(3*t+71.56°)]*u(t)

Q5) Compute the output y(t) of the systems below. In all cases, consider the system with zero initial conditions. TIP: use the convolution table and remember the properties of convolution. a) h(t) = 3 exp(-2t) u(t) and input x(t) = 2 exp(-2t) u(t) Q5.) a) h(t) = 3 exp(-2t) u(t) and input x(t) = 2 exp(-2t) u(t) (A) conv(x(t),h(t)) = 6texp(-2t)u(t) (B) conv(x(t),h(t)) = texp(-t)u(t) C) conv(x(t),h(t)) = 2texp(-t)u(t) (D) conv(x(t),h(t)) = 5exp(-2t)u(t) b) h(t) = 28(t)- 4 exp(-3t) u(t) and input x(t) = 3 u(t) Q5.) b) h(t) = 28(t) - 4 exp(-3t) u(t) and input x(t) = 3 u(t) A) conv(x(t),h(t)) = u(t) + 2(1-exp(-3t))u(t) (B) conv(x(t),h(t)) = 7u(t) + 9(1-exp(-3t))u(t) C) conv(x(t),h(t)) = 4u(t)- (1-exp(-3t))u(t) (D) conv(x(t),h(t)) = 6u(t) - 4(1-exp(-3t))u(t) c) h(t) = 2 exp(-t) u(t) and input x(t) = 4 exp(-2t) cos(3t) u(t) Q5.) c) h(t) = 2 exp(-t) u(t) and input x(t) = 4 exp(-2t) cos(3t) u(t) (A) conv(x(t),h(t)) = 6[0.1exp(-3t) - 0.6exp(-2t)cos(3t+71.56°)]u(t) B) conv(x(t),h(t)) = [0.2exp(-t) - 0.125exp(-2t)cos(3t+71.56°)]u(t) (C) conv(x(t),h(t)) = 8[0.1exp(-t) - 0.316exp(-2t)cos(3t+71.56°)]u(t) (D) conv(x(t),h(t)) = 8[0.1exp(-t) - 0.316exp(-t)sin(3t+71.56°)]*u(t)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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