Q5: Analyze the single phase bridge inverter whose output voltage is a semi- square of 60% On-time at 50 Hz. The inverter is connected to 100V de source and its load is composed of 100 in series with 100mH inductance. 1. Sketch to scale load current waveform at steady-state (derive an expression for the peaks of the current in term of system parameters) and find its RMS value. 2. Sketch input current and output voltage waveforms. 3. The RMS value of output voltage and its components up to fifth harmonics. 4. Output steady-state power, power factor and power associated with each harmonics components up to fifth harmonics. 5. Find THD of the output signal. (Hint: V₁-4E/(√na) sin nß/21

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Q5: Analyze the single phase bridge inverter whose output voltage is a semi-
square of 60% On-time at 50 Hz. The inverter is connected to 100V de source
and its load is composed of 100 in series with 100mH inductance.
1. Sketch to scale load current waveform at steady-state (derive an expression for
the peaks of the current in term of system parameters) and find its RMS value.
2. Sketch input current and output voltage waveforms.
3. The RMS value of output voltage and its components up to fifth harmonics.
4. Output steady-state power, power factor and power associated with each
harmonics components up to fifth harmonics. 5. Find THD of the output signal.
[Hint: V₁ =4E/(√na) sin nß/2]
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Transcribed Image Text:Q5: Analyze the single phase bridge inverter whose output voltage is a semi- square of 60% On-time at 50 Hz. The inverter is connected to 100V de source and its load is composed of 100 in series with 100mH inductance. 1. Sketch to scale load current waveform at steady-state (derive an expression for the peaks of the current in term of system parameters) and find its RMS value. 2. Sketch input current and output voltage waveforms. 3. The RMS value of output voltage and its components up to fifth harmonics. 4. Output steady-state power, power factor and power associated with each harmonics components up to fifth harmonics. 5. Find THD of the output signal. [Hint: V₁ =4E/(√na) sin nß/2] ← 48 Stitch It!
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