Q4. a) According to the following wavefunction, where is the radial node located? 1 /212 A. 1a0 B. 200 C. 4a0 D. 6a0 E. 8a0 b) A. 1s B. 2s C. 2p D. 3s E. 3p F. 3d nim, (r, 0, 0); = 3 1 81 π) do ao 1 6r - 1²/)e -r e3a0 cose Which atomic orbital does the following wavefunction represent? 1 3 1\2/6r - 40(2) Unim, (r, 0,4 1‚¢) = = 81 ao -r e3ao cose

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Physical chemistry: Answer question 4 parts a and b
**Question 4**

**a)** According to the following wavefunction, where is the radial node located?

\[
\psi_{nlm_l}(r, \theta, \phi) = \frac{1}{81} \left( \frac{2}{\pi} \right)^{\frac{1}{2}} \left( \frac{1}{a_0} \right)^{\frac{3}{2}} \left( \frac{6r}{a_0} - \frac{r^2}{a_0^2} \right) e^{-\frac{r}{3a_0}} \cos \theta
\]

A. \(1a_0\)  
B. \(2a_0\)  
C. \(4a_0\)  
D. \(6a_0\)  
E. \(8a_0\)  

**b)** Which atomic orbital does the following wavefunction represent?

\[
\psi_{nlm_l}(r, \theta, \phi) = \frac{1}{81} \left( \frac{2}{\pi} \right)^{\frac{1}{2}} \left( \frac{1}{a_0} \right)^{\frac{3}{2}} \left( \frac{6r}{a_0} - \frac{r^2}{a_0^2} \right) e^{-\frac{r}{3a_0}} \cos \theta
\]

A. 1s  
B. 2s  
C. 2p  
D. 3s  
E. 3p  
F. 3d
Transcribed Image Text:**Question 4** **a)** According to the following wavefunction, where is the radial node located? \[ \psi_{nlm_l}(r, \theta, \phi) = \frac{1}{81} \left( \frac{2}{\pi} \right)^{\frac{1}{2}} \left( \frac{1}{a_0} \right)^{\frac{3}{2}} \left( \frac{6r}{a_0} - \frac{r^2}{a_0^2} \right) e^{-\frac{r}{3a_0}} \cos \theta \] A. \(1a_0\) B. \(2a_0\) C. \(4a_0\) D. \(6a_0\) E. \(8a_0\) **b)** Which atomic orbital does the following wavefunction represent? \[ \psi_{nlm_l}(r, \theta, \phi) = \frac{1}{81} \left( \frac{2}{\pi} \right)^{\frac{1}{2}} \left( \frac{1}{a_0} \right)^{\frac{3}{2}} \left( \frac{6r}{a_0} - \frac{r^2}{a_0^2} \right) e^{-\frac{r}{3a_0}} \cos \theta \] A. 1s B. 2s C. 2p D. 3s E. 3p F. 3d
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