(q4) What is the frequency of the first harmonic? Let's say you now measure the length of the string and find that it is 2 meters. You then measure the mass of the string and find that it is .0094 kg. 0.0094kg / 2 = 0.0047 (95) Using the frequency and wavelength of the first harmonic what is the Tension in the string? (1) v = λƒ (2) v = √√ (3)µ = m/l

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Questions 4 and 5

(q1) how many wavelengths are there?
There is one full wavelength.
(q2) consider this to be the string of an instrument. What is the harmonic?
The harmonic would be the second harmonic due to only having about one full
wavelength.
(q3) How many nodes and anti-nodes are there?
Considering the beginning and the end, there are essentially 3 nodes and two
antinodes.
(q4) What is the frequency of the first harmonic?
Let's say you now measure the length of the string and find that it is 2 meters. You then measure
the mass of the string and find that it is .0094 kg.
0.0094kg / 2 = 0.0047
(95) Using the frequency and wavelength of the first harmonic what is the Tension in the string?
(1) v = Aƒ (2) v = √√ (3)µ = m/l
Transcribed Image Text:(q1) how many wavelengths are there? There is one full wavelength. (q2) consider this to be the string of an instrument. What is the harmonic? The harmonic would be the second harmonic due to only having about one full wavelength. (q3) How many nodes and anti-nodes are there? Considering the beginning and the end, there are essentially 3 nodes and two antinodes. (q4) What is the frequency of the first harmonic? Let's say you now measure the length of the string and find that it is 2 meters. You then measure the mass of the string and find that it is .0094 kg. 0.0094kg / 2 = 0.0047 (95) Using the frequency and wavelength of the first harmonic what is the Tension in the string? (1) v = Aƒ (2) v = √√ (3)µ = m/l
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