Q4 : Find dy /dx x2sinx Y = (1+x2)2V1+x

Q: (х3 + 3х)dx х1/2

A: Thus the integration is a process of finding anti derivative of a function . There are basically two…

Q: · (x−1)² √x d) f - dx =

A: To evaluate the following integral.

Q: Evaluate Sdx dx where A = 5x²-3x+2 and B = x³ - 2x². B

A: Evaluatedxwhere A = 5x2-3x+2B = x3-2x2i.e.

Q: Find: A. (x₂+2x)dx [12xdx B.

A:

Q: (x² - 12x + 9) dx (x²-3x + 2)²

A:

Q: Find Df, Rf : Y= 3/(2x+1)

A:

Q: 1 V4–x² 6. 4-x

A:

Q: (b) / 54x+7 dx

A: Topic :- application of integration

Q: Evaluate (x² + y²) dxdy

A:

Q: Solve (5x + 9y) dx + (9x+ 5y) dy

A:

Q: –dx (1 +x) (x+1)Vx² +2x-2

A:

Q: dx Jx (x +1)

A:

Q: dx Vx? + 2x + 5

A:

Q: Evaluate: 3 f(-x² + 4x-1)dx 1

A:

Q: Vx+I dx. Vx +1

A:

Q: d dx arctan(11x)

A: We are required to find:

Q: x2+1 - dx x4-x²+1

A:

Q: 2 dx 8x + 9

A: To find the value of given integration  We use some basic results of integration and substitution

Q: (x + 4) dx (x + 2) Vx +. 5

A: To evaluate the integral: ∫x+4(x+2)x+5dx Direct integration is not possible, so we will use the…

Q: xdy = (y - Vx² + y²) dx

A:

Q: 1 dx x² + 6x + 9

A: We have to evaluate the integral: ∫1x2+6x+9dx Rewriting the integral,…

Q: (х + 3)2 dx. J V40 – 6x - x²

A: Evaluate ∫x+3240-6x-x2dx=?

Q: Integrate x sqrt of (x+4) dx using algebraic substitution

A:

Q: Compute 3+r+1 dx x2

A: Given : ∫233x2+2x+1x2dx

Q: Evaluate f(3r2 - V5x + 2)dx.

A:

Q: dx 5. x/2 +x/3

A:

Q: dx Vx + 1

A:

Q: S V2 + 3x da

A: Let 2+3x be t

Q: xy2 = 8 at (2,2)

A: Substitute x=2 and y=2 in the given function xy2

Q: 1 = f(y-x(2-x))dx 21

A: Given: I=∫02δy-x2-x dxTo find: The value of the given integral.

Q: 8.) Find of y3 = x* + 3x d?y dx2

A:

Q: +9 J4 (12x² - 8x+10) dx

A: