Q4 Choose the correct answer..1. The sampling method is one of the methods of data collection(a) true (b) false2. The mode can be found from the ascending aggregate curve(a) true (b) false3. Variance is one type of measure(a) central tendency (b) standard numbers (e) Dispersion.4. properties of the arithmetic mean(a) Enter all values into his account (b) Enter some values into his account (c) Can be calculatedgraphically (d) no is affected by outliers5. if the scores of samples of students are11 12 10 11 16 11 15then mode is:(a)15(b)11(c)106. if the scores of samples of students are16 12 10 11 14 13 15 then median is(a)13 (b)12 (c)117-The probability that the event P(E) will accur is betweena 0

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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O Macmillan Learning The domestic cat, Felis catus, is a domesticated furry creature often kept as a pet in many countries. Suppose a volunteer at a local animal shelter wanted to find out a little more about the cats in her care. The volunteer carefully measured the height for the 10 fully grown adult cats at her shelter. The height measurements were taken from the base of the foreleg to the shoulder. The table shows the results of the measurements. Calculate the mean, variance, and standard deviations for cat height for the sample of shelter cats. Report all your answers to two decimal points. mean: variance: standard deviation: in in² in Sample 1 2 3 4 5 6 7 8 9 10 Height (in) 10.5 13 7.7 7.5 9.55 10.5 10.85 12.3 8.15 7.85
Which of these is an advantage of using a transformed score when reporting the score of an individual case? a. Transformed scores will allow the mean score to be reported. b. Transformed scores will be reported on the nominal level. c. Transformed scores provide a context for the individual's score d. Transformed scores provide a measure of variability.
Data was collected about the number of text messages a sample of college students received in the last day. In this particular sample, most students received few text messages, but a small number of students received a very large number of text messages. Two measures of center were computed for this sample: 15.6 and 20.2. One of these measures is the mean and one is the median. Which measure must be the median? 1 The median is 20.2 because the distribution of number of text messages would be skewed to the left. 2 The median is 20.2 because the distribution of number of text messages would be skewed to the right. 3 The median is 15.6 because the distribution of number of text messages would be skewed to the left. 4 The median is 15.6 because the distribution of number of text messages would be skewed to the right.
The chart below represents the number of inches of snow for a seven-day period. Sunday Monday Tuesday Wednesday Thursday Friday Saturday 2 5 3 10 0 4 2 Find the mean, median, and mode. Which is the best measure of central tendency? Remove Wednesday from the calculations. How does that impact the three measures of central tendency? Describe the effect outliers have on the measures of central tendency.
Ti A fitness instructor at a large gym would like to know if the individuals that take fitness classes in the morning tend to get in a greater number of steps than individuals that take evening fitness classes. She selects a random sample of 10 individuals that take fitness classes in the morning and 10 individuals that take fitness classes in the evening. She gives each person a step-counting At 10 device to wear for one week. At the end of the week she collects the devices and calculates the mean and standard deviation of the number of steps taken by the individuals in each group. Let uM = the true mean number of steps taken by all individuals who take fitness classes in the morning and HE = the true mean number of steps taken by all individuals who take fitness classes in the evening. What are the appropriate hypotheses for this test? O Ho: HM - HE = 0; Ho: HM - HE 0; H: HM - HE = 0 O Ho: HM HE = 0; Ha: HM - HE > 0 O Ho: HM HE < 0; H HM - HE = 0 O Ho: HM - HE - 0: H HM - HE #0
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