Q4\ Calculate the increase in stress for each segment of the compound bar if the temperature increases by 100°F. Assume that the supports are unyielding and that the bar is suitably braced against buckling. Steel A = 1.5 in? E = 29 x 10 psi a = 12.8 x 10*/°F a = 6.5 x 10*/ oF Aluminum A = 2.0 in? E = 10 x 10° psi 10 in 15 in

Q4\ Calculate the increase in stress for each segment of the compound bar if the temperature increases by 100°F. Assume that the supports are unyielding and that the bar is suitably braced against buckling. Steel A = 1.5 in? E = 29 x 10 psi a = 12.8 x 10/°F a = 6.5 x 10/ oF Aluminum A = 2.0 in? E = 10 x 10° psi 10 in 15 in

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The rigid bar is supported by a smooth pin and two rods as shown. Neglect the weight of the rigid bar. The assembly is initially stress-free. Determine the stress in each rod if the temperature increases by 25°C after a load W = 100 kN is applied. The steel rod has an area of 320 mm² with a = 11.7 um/ ( m°C ) and E = 200 GPa. For the bronze rod, it has an area of 1380 mm? with a = 18.9 µm/ ( m°C ) and E = 83 GPa. Bronze | 3 m Steel | 1.5 m 1.0 m - - 2.5 m +1.5 m→
A
3) An bronze rod is rigidly attached between a aluminum rod and a steel rod as shown. Axial loads are applied at the positions indicated. Find the maximum allowable value of P that will not exceed a stress in steel of 140MPA, in aluminum of 90MPA or in bronze of 100MPа. Aluminum A = 500mm? Bronze A = 200mm? Steel A = 150mm2 2P ЗР L st = 1.2m L br = 2m Lal = 3.5m
The steel bars are firmly attached to rigid supports. Initially the temperature is 840F. Determine the stress in bars AC and CB when the temperature becomes -600F. Use E = 29 x 106 psi and α = 6.50 x 10-6/ 0F.
3. The rigid bar ABC is pinned at B and attached to the two vertical rods. Initially, the bar is horizontal and the vertical rods are stress-free. Determine the stress in the steel rod if the temperature of the both rods is decreased by 30°C. Neglect the weight of bar ABC. Steel L=0.9 m A 300 mm E= 200 x 10 N/m' a= 11.7 um/(m C) Aluminum L=1.2 m A = 1200 mm E = 70 x 10 N/m a= 23 pum/(m "C) Answer: Ost B 0.6 m 1.2 m
Determine the normal stress and change in length of the aluminum rod if the temperature was raised by 125°C. The 0.5-mm gap exists at 20°C. q = 5 t = 0
3. The material is subjected to biaxial loading producing uniform normal stress ox and o, as shown. The strains are e, = -0.00065 and e, = -0.00040. Use E = 207 GPa and v = 0.35. Determine the following: (a) oz. Indicate tension or compression. Use 2 decimal places. (b) ơy. Indicate tension or compression. Use 2 decimal places. (c) Change in the thickness of the material. Indicate elongation or contraction. Use 5 decimal places and scientific notation of x 10-3 (Example: . (25 pts) x 10-3) y Oy x. Oy t = 16 mm
5. The rigid bar of negligible weight is pinned at O and attached to two vertical rods. Assuming that the rods were initially stress-free, what is the largest load P that can be applied without exceeding stresses of 150 MPa in the steel rod and 70 MPa in the bronze rod? -2 m- -1.5 m- 1.5 m- Bronze A = 300 mm2 E = 83 GPa L=2 m Steel A = 900 mm2 E = 200 GPa L = 1.5 m
Question 2) Knowing that a 0.02-in. gap exists when the temperature is 75 °F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. Bronze A = 2.4 in² E = 15 x 10 psi a = 12 x 10-6/°F -18 in.- Aluminum A = 2.8 in² E = 10.6 x 105 psi a = 12.9 x 10-6/°F