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Q4 @ (a) About 20=0 we have COS 2: 1- 2² + 2 + - 21+... 24 4! وقال Therefore, plugging 1/2 instead of z cos 1/2 = 1 - we obtain ....+10 212 - 1+ 82 + 12.2 and 4 2+ cos ½ ½ 2 = 24 ( 1 - 1/4 1/11 + 1/8 41 - 1/12 1/r+... » + 12-12 1/4 1/1 - 1/3 11 + 1/12 181 001 = 24-1/11 + 2° (-1)^-1 n=1 (2n+2)! Zan -

Q4 @ (a) About 20=0 we have COS 2: 1- 2² + 2 + - 21+... 24 4! وقال Therefore, plugging 1/2 instead of z cos 1/2 = 1 - we obtain ....+10 212 - 1+ 82 + 12.2 and 4 2+ cos ½ ½ 2 = 24 ( 1 - 1/4 1/11 + 1/8 41 - 1/12 1/r+... » + 12-12 1/4 1/1 - 1/3 11 + 1/12 181 001 = 24-1/11 + 2° (-1)^-1 n=1 (2n+2)! Zan -

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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what is the common trick or way to sum a series in sigma form?

Q4 @ (a) About 20=0 we have COS 2: 1- 2² + 2 + - 21+... 24 4! وقال Therefore, plugging 1/2 instead of z cos 1/2 = 1 - we obtain ....+10 212 - 1+ 82 + 12.2 and 4 2+ cos ½ ½ 2 = 24 ( 1 - 1/4 1/11 + 1/8 41 - 1/12 1/r+... » + 12-12 1/4 1/1 - 1/3 11 + 1/12 181 001 = 24-1/11 + 2° (-1)^-1 n=1 (2n+2)! Zan -
Transcribed Image Text:Q4 @ (a) About 20=0 we have COS 2: 1- 2² + 2 + - 21+... 24 4! وقال Therefore, plugging 1/2 instead of z cos 1/2 = 1 - we obtain ....+10 212 - 1+ 82 + 12.2 and 4 2+ cos ½ ½ 2 = 24 ( 1 - 1/4 1/11 + 1/8 41 - 1/12 1/r+... » + 12-12 1/4 1/1 - 1/3 11 + 1/12 181 001 = 24-1/11 + 2° (-1)^-1 n=1 (2n+2)! Zan -
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