(Q3) Let X₁ equal the fill weight in June and X2 the fill weight in October for an 8 kilogrambox of industrial bleach. Test the hypothesisHo 12 vs H₁: μμgiven that ni = 90 observations of X₁ yielded 1observations of X2 yielded 2 = 8.07, 82 = 0.054.=8.10, 810.117 and n₂ = 110(i) What is your conclusion if α = 0.05?(ii) What is the approximate p-value of this test?

To test the hypothesis H0:μ1=μ2H1:μ1=μ2using the two-sample t-test for the means of two…

Answered: (Q3) Let X₁ equal the fill weight in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A new cream that advertises that it can reduce wrinkles and improve skin was subject to a recent study. A sample of 54 women over the age of 50 used the new cream for 6 months. Of those 54 women, 43 of them reported skin improvement(as judged by a dermatologist). Is this evidence that the cream will improve the skin of more than 60% of women over the age of 50? Test using α=0.05. test statistics z= The final conclustion is A. There is not sufficient evidence to reject the null hypothesis that p=0.6. That is, there is not sufficient evidence to reject that the cream can improve the skin of more than 60% of women over 50.B. We can reject the null hypothesis that p=0.6 and accept that p>0.6. That is, the cream can improve the skin of more than 60% of women over 50.
Preliminary data analysis indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the t-test using the critical-value approach. %3D X = 44.2 and s = 7.3 Use a significance level of a = 0.05 to test the claim that u 35.8. The sample data consists of 10 scores for which H:µ±35.8 0 Н и-35.8 Test statistics: t=3.64 Critical Value: t=+/-2.262 H:µ=35.8 Reject There is sufficient evidence to support the claim that the mean is different from 35.8. П. : и 3 44.2 0. H:µ±44.2 a. Test statistics: t=3.64 Critical Value: t= +/- 2.262 H:µ=44.2 Н, There is sufficient evidence to support the claim that the mean is different from 44.2. Reject
You run a regression analysis on a bivariate set of data (n=89n=89). You obtain the regression equationy=3.875x+33.509y=3.875x+33.509with a correlation coefficient of r=0.837r=0.837 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 140 on the response variable.What is the predicted explanatory value?x =
Please no written by hand solution and no img
You run a regression analysis on a bivariate set of data (n=19n=19). You obtain the regression equationy=1.761x+1.382y=1.761x+1.382with a correlation coefficient of r=0.876r=0.876 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 160 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
You are conducting quality control for a company that manufactures LED displays. The factory you are assessing is supposed to have a manufacturing defect rate of 1 in 100 LED displays. As part of your assessment, you want to verify this defect rate by analyzing a random sample of LED displays. You are planning to randomly sample 1500 displays from this factory and observe how many of them contain manufacturing defects. Let Zi be equal to 1 if the i’th display has a defect and 0 otherwise, for i = 1,...,1500. (a) What is the statistic that you will use to estimate the defect rate for this factory? How do you compute it using Z1, Z2, . . . , Z1500? (b) Assuming that the true defect rate for this factory is in fact 1 in 100 displays, can we approximate the sampling distribution of the statistic that you selected in part (a) using a normal distribution? Please state and check the requirements for applying the approximation, and identify the mean and standard deviation of the normal…
You run a regression analysis on a bivariate set of data (n=21n=21). You obtain the regression equationy=0.402x+19.831y=0.402x+19.831with a correlation coefficient of r=0.916r=0.916 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 120 on the response variable.What is the predicted explanatory value?x
please show all steps USING EXCEL ONLY FORMULAS
The t statistic for a test of Ho u 15 H₁ μ<15 based on n = 10 observations has the value t = -1.61. (a) What are the degrees of freedom for this statistic?
Suppose that we are testing H0: µ = µ0 versus H1: µ > µ0. Calculate the P -value for the following observed values of the test statistic (round all answers to 4 decimal places. (a)z0 = 2.45, (b)z0 = -1.53, (c)z0 = 2.15, (d)z0 = 1.95, (e)z0 = -0.25.
12% of all college students volunteer their time. Is the percentage of college students who are volunteers smaller for students receiving financial aid? Of the 374 randomly selected students who receive financial aid, 41 of them volunteered their time. What can be concluded at the αα = 0.05 level of significance? The test statistic ? z t Correct = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.)
J 2

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