Q3: find the solution of f(x) = 4x cos(x) -1 using Newton Method to the error < 0.00001 Work in radian mode Note: The solution 0.4726 %3D
Q3: find the solution of f(x) = 4x cos(x) -1 using Newton Method to the error < 0.00001 Work in radian mode Note: The solution 0.4726 %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Question
Solve #3
![Finding Roots Homework
Q1: Determine the root of the given equation
f(x) = 10 – x² for x e [2,4]
using bisection method and error < 1%
Note: 3.161 is the approximated solution
Q2: find the solution of x = 2x2 – 2x - 5 using fixed point iteration to the sixth
iteration
Note: The solution 1.6
Q3: find the solution of f(x)
= 4x
cos(x) - 1 using Newton Method to
the error < 0.00001
Work in radian mode
Note: The solution = 0.4726
%3D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5fc83c76-df38-48d4-9de4-247e7fbb3676%2Fcc38c164-189d-4de7-811b-483c0503bac3%2Fb7eclqj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Finding Roots Homework
Q1: Determine the root of the given equation
f(x) = 10 – x² for x e [2,4]
using bisection method and error < 1%
Note: 3.161 is the approximated solution
Q2: find the solution of x = 2x2 – 2x - 5 using fixed point iteration to the sixth
iteration
Note: The solution 1.6
Q3: find the solution of f(x)
= 4x
cos(x) - 1 using Newton Method to
the error < 0.00001
Work in radian mode
Note: The solution = 0.4726
%3D
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