Q3 A car A is travelling along a straight path, while a lorry B is travelling along a circular path having a radius of curvature of 200 m as shown in Figure Q3. At the instant shown, car A travel at the velocity of (150+X) km/h while lorry B travel at the velocity of 80 km/h. Also at this instant, car A has an increase velocity of 7000 km/h? and lorry B has a decrease velocity of 4500 km/h?. The angle between straight path of car A and the horizontal line is 0=65°. (a) Calculate the magnitude and direction of velocity of lorry Bwith respect to ar (b) Determine the magnitude and direction of acceleration of lorry B as measured by the driver of car A. Use your matrix number by adding the last three digits to get the value of X on the velocity of car A. The value of X will then need to be added with the digit of 150 as follows; Example; If your matrix number is AD190251, Velocity of car A, VA=150 +X km/h X = (2 + 5 + 1) = 8 Therefore, the velocity of car A, VA = 150 + X, = 150 + 8 = 158 km/h.