Q2Silver wire with cross section area 0.923mm2 , the resistivity = 10.49g/cm3 and the molar mass M=107.9g/mol, if the current pass though the wire is 0.123mA, calculate : 1.The electron density 2.The current density 3.Drift speed (Va=1.42*10* m/s) %3D (n=5.855*1028 e/m³) (j=133.26A/m2)
Q2Silver wire with cross section area 0.923mm2 , the resistivity = 10.49g/cm3 and the molar mass M=107.9g/mol, if the current pass though the wire is 0.123mA, calculate : 1.The electron density 2.The current density 3.Drift speed (Va=1.42*10* m/s) %3D (n=5.855*1028 e/m³) (j=133.26A/m2)
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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![Q2Silver wire with cross section area 0.923mm2
the resistivity = 10.49g/cm³ and the molar mass
M=107.9g/mol, if the current pass though the
wire is 0.123mA, calculate :
1.The electron density
2.The current density (j-133.26A/m2)
3.Drift speed (va=1.42*10* m/s)
(n=5.855*1028 e/m³)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faa4758af-25f8-4b18-9ebc-6c40d09d7470%2Fdc024ed8-9868-48dd-8ca8-4d836210f5cc%2F2cafgi6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2Silver wire with cross section area 0.923mm2
the resistivity = 10.49g/cm³ and the molar mass
M=107.9g/mol, if the current pass though the
wire is 0.123mA, calculate :
1.The electron density
2.The current density (j-133.26A/m2)
3.Drift speed (va=1.42*10* m/s)
(n=5.855*1028 e/m³)
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