Q2\3-Functions f and g are defined by f(x) = 1/x + 3x and %3D * .g(x) = -1/x + 6x - 4 find (f + g)(x) and its domain %3D (f + g)(x) = -9 x -4, Domain of f + g is (-00 , 0) U (0, + c0) (f + g)(x) = 9 x+ 4,Domain of f + g is (-00, + oo) (f + g)(x) = 9 x - 4, Domain of f + g is (-00, 0) U (0,+ o0) ssi O

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Q2\3-Functions f and g are defined by f(x) = 1/x + 3x and
.g(x) = -1/x + 6x - 4 find (f + g)(x) and its domain
(f + g)(x) = -9 x -4, Domain of f + g is (-00 , 0) U (0, + co) O
%3D
(f + g)(x) = 9 x+ 4 ,Domain of f + g is (-00 , + o0) O
(f + g)(x) = 9 x - 4, Domain of f + g is (-00, 0) U (0, + oo) O
sssi O
Q2\4- Find the domain and range of the function (x+1)/(3-x)
Domain = (-00,3) U (3, 00), Range = (-00,-1) U (-1, 0) O
Domain = (-00,3]U (3, 00), Range = (-00,-1) U (-1, 00) O
Domain = (-00,3) U (3, c0), Range (-00,1) U (1, o0) O
ssi O
Transcribed Image Text:Q2\3-Functions f and g are defined by f(x) = 1/x + 3x and .g(x) = -1/x + 6x - 4 find (f + g)(x) and its domain (f + g)(x) = -9 x -4, Domain of f + g is (-00 , 0) U (0, + co) O %3D (f + g)(x) = 9 x+ 4 ,Domain of f + g is (-00 , + o0) O (f + g)(x) = 9 x - 4, Domain of f + g is (-00, 0) U (0, + oo) O sssi O Q2\4- Find the domain and range of the function (x+1)/(3-x) Domain = (-00,3) U (3, 00), Range = (-00,-1) U (-1, 0) O Domain = (-00,3]U (3, 00), Range = (-00,-1) U (-1, 00) O Domain = (-00,3) U (3, c0), Range (-00,1) U (1, o0) O ssi O
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