Q2. Write a C program to find the result of the following series by using power function. The program gets the value of y from the user. y++++ y 56 ... + 112 8. Example Run #1: Enter the value of y: 1.2 The result is 1626.16 Project Name: LG8_2 File Name: Q2.cpp Example Run #2: Enter the value of y: 0.25 The result is 0.14
Q2. Write a C program to find the result of the following series by using power function. The program gets the value of y from the user. y++++ y 56 ... + 112 8. Example Run #1: Enter the value of y: 1.2 The result is 1626.16 Project Name: LG8_2 File Name: Q2.cpp Example Run #2: Enter the value of y: 0.25 The result is 0.14
C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter5: Repetition Statements
Section5.6: Nested Loops
Problem 2E
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What am i doing wrong? Also, can you send me full code of the problem?
![Q2. Write a C program to find the result of the following series by using power function. The program gets the value of y from the
user.
y56
y +
8.
112
Example Run #1:
Enter the value of y: 1.2
The result is 1626.16
Project Name: LG8_2
File Name: Q2.cpp
Example Run #2:
Enter the value of y: 0.25
The result is 0.14](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc82a4c0a-b11a-45d4-89e3-566f4e27e8c9%2F78ecc6c6-c9bf-4e3b-86de-a1584252ebbf%2Fn4qod6s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2. Write a C program to find the result of the following series by using power function. The program gets the value of y from the
user.
y56
y +
8.
112
Example Run #1:
Enter the value of y: 1.2
The result is 1626.16
Project Name: LG8_2
File Name: Q2.cpp
Example Run #2:
Enter the value of y: 0.25
The result is 0.14
![Search (Ctrl+0)
Q1a
Debug
x86
Local Windows Debugger
x Q1d.cpp
Q1c.cpp
Q1b.cpp
Q1a.cpp
(Global Scope)
9 main(void)
int n;
double sum = 0,y,x;
printf("Enter the value of y: ");
scanf (" %1f",
n = 2;
while (n <= 56)
{
x = pow(y, n) / (2 * n);
sum = sum + x;
n = n + 1;
}//end of while
sum = sum + y;
printf("The result is %.2f\n",sum);
Ln: 28
Ch: 2
MIXED
A2
t from:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc82a4c0a-b11a-45d4-89e3-566f4e27e8c9%2F78ecc6c6-c9bf-4e3b-86de-a1584252ebbf%2F7n2w0su_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Search (Ctrl+0)
Q1a
Debug
x86
Local Windows Debugger
x Q1d.cpp
Q1c.cpp
Q1b.cpp
Q1a.cpp
(Global Scope)
9 main(void)
int n;
double sum = 0,y,x;
printf("Enter the value of y: ");
scanf (" %1f",
n = 2;
while (n <= 56)
{
x = pow(y, n) / (2 * n);
sum = sum + x;
n = n + 1;
}//end of while
sum = sum + y;
printf("The result is %.2f\n",sum);
Ln: 28
Ch: 2
MIXED
A2
t from:
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