Q2. The surface x 2 is the boundary between two dielectrics. The dielectric in Region 1 (x < 2) has relative permittivity = 3.5 and the dielectric in Region 2 (x > 2) has relative permittivity = 1.5. If the electric flux density at the boundary in Region 2 is: D2 = 12x – 6ỹ + 92, find E1, D1, E2, 0, and 02. %3D
Q2. The surface x 2 is the boundary between two dielectrics. The dielectric in Region 1 (x < 2) has relative permittivity = 3.5 and the dielectric in Region 2 (x > 2) has relative permittivity = 1.5. If the electric flux density at the boundary in Region 2 is: D2 = 12x – 6ỹ + 92, find E1, D1, E2, 0, and 02. %3D
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Transcribed Image Text:Q2.
The surface x 2 is the boundary between two dielectrics. The dielectric in Region 1
(x < 2) has relative permittivity = 3.5 and the dielectric in Region 2 (x > 2) has relative permittivity
= 1.5. If the electric flux density at the boundary in Region 2 is: D2 = 12x – 6ỹ + 92, find E1, D1,
E2, 0, and 02.
%3D
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