I would like the solution for this problem. Not sure how to get the values out of the info I got. d. What is the tension in the string?e. How much Mass M is hanging on the end of the string?f. How long will it take for the stopper to move around the circular path 10 times? Q2..A rubber stopper, which has a mass of m= 14.5 grams, is tied to the end of a stringwhich is threaded through a glass tube. You then spin the rubber stopper about yourhead in a horizontal circle as shown to the right. The stopper sags B= 18.0° belowthe horizontal as shown and the distance from the top of the tube to the stopper isL = 1.25 m.a. Draw the freebody diagram showing each of the forces acting on the rubberstopper.'mb. What will be the magnitude of the centripetal force acting on the stopper?c. What is the speed of the stopper?

(a) Draw the free-body diagram of the forces acting on the rubber stopper. Here, L is the length of the thread, R is the radius of the circle, FC is the centripetal force and T is the tension.(d) Calculation: Write the expression for the net vertical force on the stopper. Tsinβ=mg Substitute the values. Tsin18.0°=14.5 g1 kg1000 g9.8 m/s2T=0.459 N Thus, the tension in the thread is 0.459 N.(b) Calculation: Write the expression for the net horizontal force on the stopper. FC=Tcosβ Substitute the values. FC=0.459 Ncos18.0°=0.436 N Thus, the centripetal force is 0.436 N.(c) Calculation: Write the expression for the radius of the circle. R=Lcosθ Write the expression for the centripetal force. F=mv2R Substitute the value of R. F=mv2Lcosθ Substitute the values. 0.436 N=14.5 g1 kg1000 gv21.25 mcos18.0v=35.74 m/sv=5.97 m/s Thus, the velocity is 5.97 m/s.