Q2. A fluid flows through a fixed (i.e., not rotating) curved pipe of uniform diameter 15 cm with a velocity of the fluid particles on the streamline along the center line of the pipe defined by V = 3t m/sec as shown in the figure below. Determine the normal acceleration and the streamline acceleration when t = 10 sec. 0.5 m +

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Please show all steps to solve this problem so your thought process is easy to follow. Also please show all formulas that you used. Subject is fluid mechanics
**Problem Statement:**

A fluid flows through a fixed (i.e., not rotating) curved pipe of uniform diameter 15 cm with a velocity of the fluid particles on the streamline along the center line of the pipe defined by \( V = 3t \) m/sec. Determine the normal acceleration and the streamline acceleration when \( t = 10 \) sec.

**Diagram Explanation:**

The diagram shows a curved pipe with a uniform diameter. The fluid flows from one end to the other along a streamline. The curvature of the pipe has a radius of 0.5 m. The direction of the fluid flow is indicated by arrows.

---

**Instructions on How to Solve:**

To determine the normal and streamline acceleration at \( t = 10 \) seconds, use the following formulas:

1. **Streamline Acceleration (\( a_s \))**:
   The streamline acceleration is the derivative of the velocity function with respect to time \( t \).

   \[
   a_s = \frac{dV}{dt}
   \]

2. **Normal Acceleration (\( a_n \))**:
   The normal acceleration for a curved path is given by:

   \[
   a_n = \frac{V^2}{r}
   \]

   where \( V \) is the velocity at \( t = 10 \) seconds and \( r \) is the radius of curvature of the pipe.

For this problem, apply the given velocity function \( V = 3t \) m/sec.

---

**Calculation Steps:**

1. **Find the Streamline Acceleration (\( a_s \)):**

   \[
   V = 3t \implies \frac{dV}{dt} = 3 \quad \text{m/s}^2
   \]

   At \( t = 10 \) sec, the streamline acceleration \( a_s \) is \( 3 \, \text{m/s}^2 \).

2. **Calculate Velocity at \( t = 10 \) seconds:**

   \[
   V = 3 \times 10 = 30 \, \text{m/s}
   \]

3. **Find the Normal Acceleration (\( a_n \)):**

   \[
   a_n = \frac{V^2}{r} = \frac{30^2}{0.5} = \frac{900}{0.5} =
Transcribed Image Text:**Problem Statement:** A fluid flows through a fixed (i.e., not rotating) curved pipe of uniform diameter 15 cm with a velocity of the fluid particles on the streamline along the center line of the pipe defined by \( V = 3t \) m/sec. Determine the normal acceleration and the streamline acceleration when \( t = 10 \) sec. **Diagram Explanation:** The diagram shows a curved pipe with a uniform diameter. The fluid flows from one end to the other along a streamline. The curvature of the pipe has a radius of 0.5 m. The direction of the fluid flow is indicated by arrows. --- **Instructions on How to Solve:** To determine the normal and streamline acceleration at \( t = 10 \) seconds, use the following formulas: 1. **Streamline Acceleration (\( a_s \))**: The streamline acceleration is the derivative of the velocity function with respect to time \( t \). \[ a_s = \frac{dV}{dt} \] 2. **Normal Acceleration (\( a_n \))**: The normal acceleration for a curved path is given by: \[ a_n = \frac{V^2}{r} \] where \( V \) is the velocity at \( t = 10 \) seconds and \( r \) is the radius of curvature of the pipe. For this problem, apply the given velocity function \( V = 3t \) m/sec. --- **Calculation Steps:** 1. **Find the Streamline Acceleration (\( a_s \)):** \[ V = 3t \implies \frac{dV}{dt} = 3 \quad \text{m/s}^2 \] At \( t = 10 \) sec, the streamline acceleration \( a_s \) is \( 3 \, \text{m/s}^2 \). 2. **Calculate Velocity at \( t = 10 \) seconds:** \[ V = 3 \times 10 = 30 \, \text{m/s} \] 3. **Find the Normal Acceleration (\( a_n \)):** \[ a_n = \frac{V^2}{r} = \frac{30^2}{0.5} = \frac{900}{0.5} =
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