Q2. A damped masS-spring oscillator consist of a mass m attached to a spring fixed at one end, as shown in Figure. Equilibrium point Figure: Damped Mass-Spring Oscillator The Newton's second law implies that the position y(t) of the mass m is govemed by the second-order differential equation my"(t) + by'(t) + ky(t) = 0 ,

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where the terms are physically identified as
[inertia] y" + [damping] y' + [stiffness] y = 0.
(a) Determine the equation of motion for a spring system when m = 36 kg,b =
12 kg/sec (which is equivalent to 12 N – sec/m), k = 37 kg/sec², y(0) = 0.7 m
and y' (0) = 0.1 m/sec.
(b) After how many seconds will the mass first cross the equilibrium point?
Transcribed Image Text:where the terms are physically identified as [inertia] y" + [damping] y' + [stiffness] y = 0. (a) Determine the equation of motion for a spring system when m = 36 kg,b = 12 kg/sec (which is equivalent to 12 N – sec/m), k = 37 kg/sec², y(0) = 0.7 m and y' (0) = 0.1 m/sec. (b) After how many seconds will the mass first cross the equilibrium point?
Q2. A damped mass-spring oscillator consist of a mass m attached to a spring fixed at one end,
as shown in Figure.
Equilibrium
point
Figure: Damped Mass-Spring Oscillator
The Newton's second law implies that the position y(t) of the mass m is govemed by the
second-order differential equation
my"(t) + by'(t) + ky(t) = 0,
Transcribed Image Text:Q2. A damped mass-spring oscillator consist of a mass m attached to a spring fixed at one end, as shown in Figure. Equilibrium point Figure: Damped Mass-Spring Oscillator The Newton's second law implies that the position y(t) of the mass m is govemed by the second-order differential equation my"(t) + by'(t) + ky(t) = 0,
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