Answered: Q2) The forward path transfer function… | bartleby

Related questions

Question

100%

Q2) The forward path transfer function is given by G(s) = 9/s(s+6). Obtain an
expression for unit step response of the system.

Expert Solution

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Blurred answer

Similar questions

A small block of mass M = 850 g is placed on top of a larger block of mass 3M which is placed on a level frictionless surface and is attached to a horizontal spring of spring constant k = 3.5 N/m. The coefficient of static friction between the blocks is μ = 0.2. The lower block is pulled until the attached spring is stretched a distance D = 1.5 cm and released.Randomized Variables M = 850 gD = 1.5 cmk = 3.5 N/m a) Calculate a value for the magnitude of the maximum acceleration amax of the blocks in m/s2. b) Write an equation for the largest spring constant kmax for which the upper block does not slip. c) Calculate a value for the largest spring constant kmax for which the upper block does not slip, in N/m.
What is the slope of a dynamically-measured period vs the quantity: √(m/k) graph.
A small piece of rounded stone perforated for threading is sliding on a wire which is hanging freely in the shape of a cosh function. Assume the stone moves with no friction. For very small displacements in x, what is the frequency of oscillation? You may use for the height of the wire and thus the height of the stone as a function of x the Taylor series expansion of cosh. G(x) =1 + x2/2 + x4/24 + ...
A block with a mass m = 2.5 kg is pushed into an ideal spring whose spring constant is k = 4520 N/m. The spring is compressed x = 0.066 m and released. After losing contact with the spring, the block slides a distance of d = 2.25 m across the floor before coming to rest. a. Write an expression for the coefficient of kinetic friction between the block and the floor using the symbols given in the problem statement and g (the acceleration due to gravity). (Do not neglect the work done by friction while the block is still in contact with the spring.)
A car with a mass m = 1000.0kg is moving on a horizontal surface with a speed v = 20.0m/s when it strikes a horizontal coiled spring and is brought to rest when the spring is compressed by a distance d = 3.0m. Calculate the spring stiffness constant k by... (a) select appropriate common equations and make appropriate substitutions that are specific to the problem, and algebraically manipulate the equations to end with an algebraic expression for the variable the problem is asking you to solve for. (b) Show the numeric substitution of given quantities and show the final numeric result. (c) Draw a free body diagram for the system and define the given quantities.
Problem 11: A small block of mass M= 350 g is placed on top of a larger block of mass 3M which is placed on a level frictionless surface and is attached to a horizontal spring of spring constant k = 1.9 N/m. The coefficient of static friction between the blocks is μ =0.2. The lower block is pulled until the attached spring is stretched a distance D = 2.5 cm and released. Randomized Variables M = 350 g D = 2.5 cm k = 1.9 N/m Part (a) Assuming the blocks are stuck together, what is the maximum magnitude of acceleration amax of the blocks in terms of the variables in the problem statement? amax = k D/(3 M+M ) ✓ Correct! Part (b) Calculate a value for the magnitude of the maximum acceleration amax of the blocks in m/s². ✓ Correct! | @mar= 0.03390 Part (c) Write an equation for the largest spring constant kmax for which the upper block does not slip. Kmax = μ (M +M) g/kl
Q.1 Consider the following equation of motion 2x + cx + 800x = 50 sin(10t) find the solution of the steady state response.
The data given would be the following: 1(t) = -9.8 m/s2 and p(1)= 10 k and d(1) = 19.8 m/s. Using this, determine the position function p(t) using antiderivatives and the initial value data
O Then we have: The equation of motion of a particle in simple harmonic motion is grven by: x(t)=1 0.1cos(wt), where x is in meters and t is in seconds. Atx = 0, the particle's velocity is v = -1.256 m/s. The period of oscilation, 1, equals O 05 sec O 3 sec 1.5 sec O 1 seci O 0 25 sec A block-spring system has a maxlum.restoring force
a. Show by substitution that the function y(t) = Ce2.5t is a solution of the differential equation y'(t) = 2.5y(t), where C is an arbitrary constant.b. Show by substitution that the function y(t) = 3.2e2.5t satisfies the initial value problem y '(t) = 2.5y(t) Differential equation y (0) = 3.2. Initial condition
Find the velocity of the block once the spring reaches its equilibrium point (delta = 0) in terms of the coefficient of kinetic friction, the mass, the spring constant, delta, gravitational acceleration, and the angle. Then find the length, L, it will reach before starting to fall. M^^^^^^^ WWW L
The springs in the figure are haO NOT equal springs. A box is placed in front of a squezed spring. Whole system is frictionless. When the box is relesed, what can be said * x= 0 m about the motion. O If the stored energy in the spring is slightly higher to the potential energy of the hill, the oscillation is infinite O It oscillates between the points infinetely O It cannot climb the hill O Oscillation is finite O If the stored energy in the spring is higher than the potential energy of the hill, the oscillation is infinite